Answer:
If a vertical line extending down from an object's CG extends outside its area of support, the object will topple
Explanation:
We can understand better this situation using a diagram with the forces acting on it.
In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.
Answer:
The deformation is 0.088289 m
The final height of the monument is 170-0.088289 = 169.911702 m
Explanation:
Thermal coefficient of marble varies between (5.5 - 14.1) ×10⁻⁶/K = α
So, let us take the average value
(5.5+14.1)/2 = 9.8×10⁻⁶ /K
Change in temperature = 35-(-18) = 53 K = ΔT
Original length = 170 m = L
Linear thermal expansion
The deformation is 0.088289 m
The final height of the monument is 170-0.088289 = 169.911702 m (subtraction because of cooling)
Given Information:
KEa = 9520 eV
KEb = 7060 eV
Electric potential = Va = -55 V
Electric potential = Vb = +27 V
Required Information:
Charge of the particle = q = ?
Answer:
Charge of the particle = +4.8x10⁻¹⁸ C
Explanation:
From the law of conservation of energy, we have
ΔKE = -qΔV
KEb - KEa = -q(Vb - Va)
-q = KEb - KEa/Vb - Va
-q = 7060 - 9520/27 - (-55)
-q = 7060 - 9520/27 + 55
-q = -2460/82
minus sign cancels out
q = 2460/82
Convert eV into Joules by multiplying it with 1.60x10⁻¹⁹
q = 2460(1.60x10⁻¹⁹)/82
q = +4.8x10⁻¹⁸ C
Answer:
h = 10000 m
Explanation:
The pressure applied at a depth of the liquid is given by:
P =ρgh
where,
P = Maximum Pressure to Survive = (1000)(Atmospheric Pressure)
P = (1000)(101325 Pa) = 1.01 x 10⁸ Pa
ρ = Density of sea water = 1025 kg/m³
g = 9.8 m/s²
h = maximum depth to survive = ?
Therefore,
1.01 x 10⁸ Pa = (1025 kg/m³)(9.8 m/s²)h
h = (1.01 x 10⁸ Pa)/(1025 kg/m³)(9.8 m/s²)
<u>h = 10000 m</u>
If the atom is neutral, it has the same number of protons as electrons. If there are 5 electrons, there are also 5 protons.
