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satela [25.4K]
3 years ago
11

The specific heat of water is 4.18 J/g•°C. How much heat does 225.0 g of water release when it cools from 85.5°C to 50.0°C? Ente

r your answer below, in whole numbers, without any commas.
Chemistry
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

33400 J

Question:

The specific heat of water is 4.18 J/g•°C. How much heat does 225.0 g of water release when it cools from 85.5°C to 50.0°C? Enter your answer below, in whole numbers, without any commas.

Sergio [31]3 years ago
4 0
The answer is 33400J
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Which of the following transports electricity between objects in a circuit?
nirvana33 [79]

Answer:

Wire.

Explanation:

The wire has movable electrons, which moves the charge and the electricity around.

Battery provides the electricity by electrical potential energy, not transport it.

The switch toggles between an open circuit and a closed one, where only the closed one has a full loop of wire to transport electricity.

And the light bulb uses electricity.

Hope this helped!

3 0
3 years ago
A few substances are arranged in the increasing order of ‘forces of attraction’ between their particles. Which one of the follow
gavmur [86]

Answer:

A.

Explanation:

PO WATER,AIR,WIND

7 0
3 years ago
Fructose-2,6-bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolys
postnew [5]

Answer:

1. Increased levels of fructose-2,6-bisphosphatase : Activate gluconeogenesis Inhibit glycolysis

2. Activation of fructose-2,6-bisphosphate (FBPase-2) : Activate glycolysis Inhibit gluconeogenesis

3. Increased glucagon levels : Activate gluconeogenesis Inhibit glycolysis

4. Activation of PFK-2 : Activate glycolysis Inhibit gluconeogenesis

5. Increased levels of CAMP : Activate gluconeogenesis Inhibit glycolysis

Explanation:

Glycolysis is the breakdown of glucose molecules in order to release energy in the form of ATP in response to the energy needs of the cells of an organism.

Gluconeogenesis is the process by which cells make glucose from other molecules for other metabolic needs of the cell other than energy production.

Glycolysis and gluconeogenesis are metabolically regulated in the cell by various enzymes and molecules.

The following shows the various regulatory methods and their effects on both processes:

1. The enzyme fructose-2,6-bisphosphatase functions in the regulation of both processes. It catalyzes the breakdown of the molecule fructose-2,6-bisphosphate which is an allosteric effector of two enzymes phosphofructokinasse-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase-1 which fuction in glycolysis and gluconeogenesis respectively.

Increased levels of fructose-2,6-bisphosphatase  activates gluconeogenesis and inhibits glycolysis by its breakdown of fructose-2,6-bisphosphate.

2. Fructose-2,6-bisphosphate increases the activity of PFK-1 and inhibits the the activity of FBPase-1. The effect is that glycolysis is activated while gluconeogenesis is inhibited.

3. Glucagon is a hormone that stimulates the synthesis of cAMP. It fuctions to activate gluconeogenesis and inhibit glycolysis.

4. Phosphosfructikinase-2, PFK-2 is an enzyme that catalyzes the formation of fructose-2,6-bisphosphate. Activation of PFK-2 results the activation of glycolysis and inhibition of gluconeogenesis.

5. Cyclic-AMP (cAMP) synthesis in response to glucagon release serves to activate a cAMP-dependent protein kinase which phosphorylates the bifunctional protein PFK-2/FBPase-2. This phosphorylation enhances the activity of FBPase-2 while inhibiting the activity of PFK-2, resulting in the  activation of gluconeogenesis and inhibition of glycolysis.

7 0
3 years ago
Trisha and her lab partner were conducting a variety of experiments to produce gases: hydrogen, oxygen, and carbon dioxide. In o
GaryK [48]

<u>Given:</u>

Volume of HCl = 150 ml

Molarity of HCl = 0.10 M

<u>To determine:</u>

The # moles of HCl

<u>Explanation:</u>

The molarity of a solution is the number of moles of a solute dissolved in a given volume

In this case:

Molarity of HCl = moles of HCl/volume of the solution

moles of HCl = Molarity * volume = 0.10 moles.L-1 * 0.150 L = 0.015 moles

Ans: A)

Moles of HCl is 0.015

7 0
4 years ago
HELP ASAP PLZ!!!
LuckyWell [14K]

Answer:

2

Explanation:

5 0
4 years ago
Read 2 more answers
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