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gtnhenbr [62]
4 years ago
9

A 5 grams sample of liquid water evaporates into gaseous water in a closed container, expanding in the process. What is the mass

after evaporation?
Chemistry
1 answer:
padilas [110]4 years ago
5 0

We have get the mass of gaseous water after evaporation in a closed container.

The mass of water vapor after evaporation is 5 grams.

In closed container, there is no exchange in mass from system to surrounding, only heat may exchange. The number of moles of water vapour remains unchanged as 5 gram water is heated in closed container.

Due to heating, liquid water gets evaporated and intermolecular distance between water molecules increases in gaseous state than liquid state and intermolecuar force of attraction decreases.

Randomness of  molecules increases in gaseous state than liquid state.  


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A first order reaction has 1/16 of the original amount left after 500 seconds. What is the half-life of the reactant in this rea
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A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

<h3>What is a first order reaction?</h3>

It is a chemical reaction in which the rate of reaction is directly proportional to the concentration of the reacting substance.

First, we will calculate the rate constant using the following expression.

ln ([A]/[A]₀) = - k × t

ln (1/16[A]₀/[A]₀) = - k × 500 s

k = 5.55 × 10⁻³ s⁻¹

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  • t is the elapsed time.

Next, we can calculate the half-life (th) using the following expression.

th = ln 2 / k = ln 2 / (5.55 × 10⁻³ s⁻¹) = 125 s

A first order reaction, with a half-life of 125 s, has 1/16 of the original amount left after 500 seconds.

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