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gtnhenbr [62]
3 years ago
9

A 5 grams sample of liquid water evaporates into gaseous water in a closed container, expanding in the process. What is the mass

after evaporation?
Chemistry
1 answer:
padilas [110]3 years ago
5 0

We have get the mass of gaseous water after evaporation in a closed container.

The mass of water vapor after evaporation is 5 grams.

In closed container, there is no exchange in mass from system to surrounding, only heat may exchange. The number of moles of water vapour remains unchanged as 5 gram water is heated in closed container.

Due to heating, liquid water gets evaporated and intermolecular distance between water molecules increases in gaseous state than liquid state and intermolecuar force of attraction decreases.

Randomness of  molecules increases in gaseous state than liquid state.  


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Explanation:

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A flask contains an equal mixture of oxygen and argon. Which of the following statements is true about the effusion of the gases
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Given that the pressure, temperature and area of effusion is constant, the rate of effusion is inversely proportional to the square root of the molecular mass of the gas.
Mr Oxygen = 32
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Calcium and titanium atoms have the same mass
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If a Ferrari, with an initial velocity of 10 m/s, accelerates at a rate of 50 m/s/s for 3 seconds, what will its final velocity
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3 0
3 years ago
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How many significant digits are in the number 2370.0?
xz_007 [3.2K]

Answer:

2370.0 contains 4 significant digits and Option (c) is correct .

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

Step-by-step explanation:

Rules for finding significant digit .

1 : Non-zero digits are always significant.

2: Any zeros between two significant digits are significant .

3: Trailing zeros in the decimal number is also significant.

As the number given be 2,370.0.  

= \frac{23700}{10}

Simplify the above

= 2370

Thus by using the rule given above.

2370.0 contains 4 significant digits.

Option (c) is correct .

As the number given be 0.00120 .  

= \frac{120}{100000}

Simplify the above

= \frac{1.20}{1000}

= 1.20\times 10^{-3}

Thus by using the rule given above.

1.20\times 10^{-3}\ contains\ three\ significant\ digit.

Option (b) is correct .

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