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Fiesta28 [93]
3 years ago
8

1. If you look at a reaction equation for a Fischer esterification reaction, you cannot tell where the oxygen comes from (acid o

r alcohol). Knowing the mechanism of this reaction, devise an experiment using O18, to help prove unequivocally where the oxygen comes from. 2 The Fischer Esterification is highly reversible and the products are only, slightly favored. State two procedures you did to help drive the reaction to the ester. 3. A student forgot to remove their silica gel beads before distillation of ester product. After distillation, his product was cloudy, indicating it was wet. Why
Engineering
1 answer:
Yanka [14]3 years ago
7 0

Answer:

Explained

Explanation:

In the experiment, an (18)O-labelled alcohol R('18)OH is used with normal unlabeled carboxylic acid RC(16)O2H:

The esterification reaction is:  

(note: the bracketed values are atomic masses)

RC(16)O_2H + R'(18)OH => RC16O18OR' + H_2(16)O

Since the alcohol is the nucleophile in this nucleophilic substitution reaction, it adds to the carbonyl group of the carboxylic acid and the (18)O atom becomes incorporated into the ester product, while the (16)OH group of the carboxylic acid is expelled as H_2(16)O.

By using mass spectroscopy to measure the mass of the ester and water products, it can be shown that each ester molecule contains one (18)O atom and one (16)O atom, while the water molecules contains only (16)O atoms.

This would prove unequivocally that the ester contains one O atom from the carboxylic acid and one O atom from the alcohol, while the water contains only O atoms from the carboxylic acid.

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There are two machines for sale that you are considering purchasing for your sawmill to produce hardwood flooring. You want to f
devlian [24]

Answer:

Machine 2 has a higher process capability index, it would be best considered for purchase.

Explanation:

Process capability index: Cpk= Min [(mean-L spec)/3sd; (U spec-mean)/3sd]

For machine 1, mean= 48mm and L spec= 46 and U spec= 50, Standard deviation sd= 0.7

Cpk= [0.952;0.952]= 0.952

For machine 2, mean= 47 and L spec= 46 and U spec= 50, Standard deviation sd= 0.3

Cpk= [1.111;3.333]= 1.111

It is clearly observed from the calculations above that the Cpk value of machine 2 is higher than that of machine 1.

Since machine 2 has a higher process capability index, it would be best considered for purchase.

4 0
3 years ago
An engineer is testing the shear strength of spot welds used on a construction site. The engineer's null hypothesis at a 5% leve
lilavasa [31]

Answer:

b) The null hypothesis should be rejected.

Explanation:

The null hypothesis is  that the mean shear strength of spot welds is at least

3.1 MPa

H0: u ≥3.1 MPa  against the claim Ha: u< 3.1 MPa

The alternate hypothesis is  that the mean shear strength of spot welds is less than 3.1 MPa.

This is one tailed test

The critical region Z(0.05) < ± 1.645

The Sample mean= x`= 3.07

The number of welds= n= 15

Standard Deviation= s= 0.069

Applying z test

z= x`-u/s/√n

z= 3.07-3.1/0.069/√15

z= -0.03/0.0178

z= -1.68

As the calculated z= -1.68  falls in the critical region Z(0.05) < ± 1.645 the null hypothesis is rejected and the alternate hypothesis is accepted that the mean shear strength of spot welds is less than 3.1 MPa

8 0
2 years ago
Question 1: Final Results = What are the values of the resistances such that the gain = -100, Rin = 1 MI2. Don't use resistances
lidiya [134]

Answer:

Explanation:

In a study of algebra, you will encounter many families of equations, or groups of

equations that share common characteristics. Of interest to us here is the family of

linear equations in one variable, a study that lays the foundation for understanding

more advanced families. In addition to solving linear equations, we’ll use the skills we

develop to solve for a specified variable in a formula, a practice widely used in science,

business, industry, and research.

A. Solving Linear Equations Using Properties of Equality

An equation is a statement that two expressions are

equal. From the expressions and

we can form the equation

which is a linear equation in one variable. To solve

an equation, we attempt to find a specific input or xvalue that will make the equation true, meaning the

left-hand expression will be equal to the right. Using

Table 1.1, we find that is a

true equation when x is replaced by 2, and is a false

equation otherwise. Replacement values that make

the equation true are called solutions or roots of the equation.

4 0
2 years ago
Free Brainliest Again
svetlana [45]

Answer:

Explanation:

thxs

4 0
3 years ago
Read 2 more answers
What is the answer ?
tigry1 [53]
Is the control group
4 0
3 years ago
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