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3 years ago

An observation which is descriptive is considered quantitative, creative, qualitive

2 answers:

4 0

Explanation: An observation is can be a collected information itself. It is an informal action, but it can be formal too and involve data collection. In descriptive observation one do not wish to modify the activity, he want it to get registered such as it would take place without his presence. In this observations are detailed and focused, in which questions about a phenomenon are carefully examined and expressed at the outset that is why it is considered quantative as well as qualitative.

Vesnalui [34]3 years ago

3 0

A descriptive observation may very well be a mixture of both quantitative and qualitative as it can utilize elements of both types. Qualitative deals with the kinds of observations that cannot be measured in numerical form. Quantitative data is just that.

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A 69 kg zebra is traveling 7 m/s east. What is the zebra’s momentum? kg-m/s

Hitman42 [59]

Linear momentum is the product of mass and velocity. In this case, it is simply:
$69\times 7 = 483 kg\cdot m/s$

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2 years ago

You are driving due north on i-81 to come to jmu with a speed of 10 m/s, suddenly you realize you forgot your book. You make a u

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first we make a U turn and travel towards home in t = 20 s

so the distance of home from initial position is

$d_1 = v*t_1$

$d_1 = 10*20 = 200 m$

Now after picking up the book we travel back with speed 20 m/s

so again after t = 20 s the displacement is given as

$d_2 = v*t = 20*20 = 400 m$

so the net displacement is given as

$\vec d = \vec d_2 - \vec d_1$

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3 years ago

Pedro is planning to model how changes in weather affect evaporation from lakes for his first experiment he wants to test how hu

Valentin [98]

Answer:

C. volume of water and temperature

Explanation:

a p e x

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3 years ago

What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?

Ainat [17]

Kinetic energy= 1/2 m v^2

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3 years ago

Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20Â°C. Container A is rigid. Container B has a 100 cm^2 pis

Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

Final Temperature of the gas in A will b GREATER than the temperature in B

Diagram of both processes on a single PV has been uploaded below,

Initial pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) / 0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial pressures in containers A and B is 3039.87 J/liters

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

Also work done = P( V₂ - V₁ )

so we substitute

375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

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2 years ago