Mountains can form many ways. a few are when divergent plates move abort and lava comes through the crack evenly forming up to what Hawaii is today. Another is when convergent plates collide moving upward forming mountains.

7 0

4 years ago

Calculate Anna's weight in newtons on Earth. (G=9.8 m/s2) Must include unit with your answer, what is it?

Pavlova-9 [17]

We know from that other question that her mass is 60 kg, and

Weight = (mass) x (gravity)

Earth weight = (60 kg) x (9.8 m/s^2)

Weight = 588 Newtons

3 0

3 years ago

Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t

BabaBlast [244]

Answer:

$-\frac{8\pi}{3}rad/s^2$

Explanation:

To solve this problem we need to apply the concept related to Angular Acceleration. We can find it through the equation

$\omega_f^2-\omega_i^2=2\alpha\theta$

Where for definition,

$\omega_i = \frac{\theta}{t}$

The number of revolution $(\theta)$ was given by 20 times, then

$\omega_i = \frac{20*2pi}{5}$

$\omega = 8\pi rad/s$

We know as well that the salad rotates 6 more times, therefore in angle measurements that is

$\theta = 6*2\pi rad = 12\pi rad$

The cook at the end stop to spin, then using our first equation,

$0-8\pi = 2\alpha (12\pi)$

re-arrange to solve $\alpha$ ,

$\alpha = \frac{-8\pi}{2*12\pi}$

$\alpha = -\frac{8\pi}{3}rad/s^2$

We can know find the required time,

$\omega_f-\omega_i = \alpha t$

Re-arrange to find t, and considering that $\omega_f=0$

$t= \frac{\omega_i}{\alpha}$

$t=\frac{-8\pi}{-8\pi/3}$

$t=3s$

Therefore take for the salad spinner to come to rest is 3 seconds with acceleration of $-\frac{8\pi}{3}rad/s^2$

6 0

3 years ago

Read 2 more answers

Write a program that calculates the average of n integers. the program should prompt the user to enter the value for n and then

ikadub [295]

#include<studio.h>

int main( )

{

int n;

int a,b,c,d,x,y;

int avarage;

printf("enter value of n:\n");

scanf("%d",&n);

printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);

scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);

sum=(a+b+c+d+x+y);

avarage=(sum/n);

print f("%d",avarage);

{

n=positive interger

}

else

{

printf ("n must be positive");

}

return 0;

}

8 0

3 years ago