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3 years ago

When a wire with a current is placed in a magnetic field,

2 answers:

8 0

When a current carrying wire is placed in a magnetic field, it experiences a mechanical force. This was discovered by Michael Faraday in 1821. The wire will not experience any mechanical force if it is placed parallel to the magnetic field. And the force will be maximum if the current carrying wire is placed in a direction perpendicular to that of the magnetic field. The force exerted on the wire is known as the Lorentz force.

cupoosta [38]3 years ago

7 0

Answer:

It makes it fast and has a bigger field

Explanation:

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Leslie is investigating which brand of cell phone has the longest lasting battery.

choli [55]

Answer:

Which battery has a longer battery life?

Explanation:

duh

4 0

3 years ago

Monochromatic light is incident on a pair of slits that are separated by 0.220 mm. The screen is 2.60 m away from the slits. (As

Naddik [55]

Answer:

$\lambda = 1.667 nm$

$\theta = 0.8681^o$

Explanation:

From the question we are told that

The distance of separation is $d = 0.220 \ mm = 0.00022 \ m$

The is distance of the screen from the slit is $D = 2.60 \ m$

The distance between the central bright fringe and either of the adjacent bright $y = 1.97 cm = 1.97 *10^{-2}\ m$

Generally the condition for constructive interference is

$d sin \tha(\theta ) = n \lambda$

From the question we are told that small-angle approximation is valid here.

So $sin (\theta ) = \theta$

=> $d \theta = n \lambda$

=> $\theta = \frac{n * \lambda }{d }$

Here n is the order of maxima and the value is n = 1 because we are considering the central bright fringe and either of the adjacent bright fringes

Generally the distance between the central bright fringe and either of the adjacent bright is mathematically represented as

$y = D * sin (\theta )$

From the question we are told that small-angle approximation is valid here.

$y = D * \theta$

=> $\theta = \frac{ y}{D}$

$\frac{n * \lambda }{d } = \frac{y}{D}$

$\lambda =\frac{d * y }{n * D}$

substituting values

$\lambda = \frac{0.00022 * 1.97*10^{-2} }{1 * 2.60 }$

$\lambda = 1.667 *10^{-6}$

$\lambda = 1.667 nm$

In the b part of the question we are considering the next set of bright fringe so n= 2

Hence

$dsin (\theta ) = n \lambda$

$\theta = sin^{-1}[\frac{ n * \lambda }{d} ]$

$\theta = sin^{-1}[\frac{ 2 * 1667 *10^{-9}}{ 0.00022} ]$

$\theta = 0.8681^o$

7 0

4 years ago

IF you are in Space and push a bowling what happens to you and the bowling ball?

Anastaziya [24]

Answer:

The bowling ball did not change size or shape- the only thing that changed was the amount of gravity that pulls on it. But the mass of the bowling ball would never change. A bowling ball with a mass of 12 pounds on earth will have the mass of 12 pounds on the moon! Mass is the amount of atoms that a space fills.

Explanation:

I hope this helps! :D

4 0

3 years ago

F.r.e.e points :]]]

Colt1911 [192]

Ok? I don’t know what you want me to do though

4 0

3 years ago

Read 2 more answers

Which body is found inside the solar system?

Digiron [165]