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Masja [62]
3 years ago
5

An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel at 1530 m/s in seawater. The time de

lay of the echo to the ocean floor and back is 6 s. ?
Physics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

d = 4590 m

Explanation:

given,

Speed of ultrasonic wave, v = 1530 m/s

time of the echo, t = 6 s

Let d be the depth of the ocean

now,

total distance travel by the ultrasonic wave = 2 d

we know,

distance = speed x t

2 d = 1530 x 6

d = 1530 x 3

d = 4590 m

Hence, the depth of the ocean floor is equal to d = 4590 m

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tekilochka [14]

Answer:

The maximum mass that can fall on the mattress without exceeding the maximum compression distance is 16.6 kg

Explanation:

Hi there!

Due to conservation of energy, the potential energy (PE) of the mass at a height of 3.32 m will be transformed into elastic potential energy (EPE) when it falls on the mattress:

PE = EPE

m · g · h = 1/2 k · x²

Where:

m = mass.

g = acceleration due to gravity.

h = height.

k = spring constant.

x = compression distance

The maximum compression distance is 0.1289 m, then, the maximum elastic potential energy will be the following:

EPE =1/2 k · x²

EPE = 1/2 · 65144 N/m · (0.1289 m)² = 541.2 J

Then, using the equation of gravitational potential energy:

PE = m · g · h =  541.2 J

m =  541.2 J/ g · h

m = 541.2 kg · m²/s² / (9.8 m/s² · 3.32 m)

m = 16.6 kg

The maximum mass that can fall on the mattress without exceeding the maximum compression distance is 16.6 kg.

6 0
3 years ago
A 263 g ball of clay falls onto a vertical spring.
Elena-2011 [213]

Answer:

d. According to the previous theorem:

(kh^2)/2-mgh-(m(2v)^2)/2=0,

126h^2-2.577h-8.236=0,

h=0.266 m.

Explanation:

3 0
2 years ago
Can anyone help with this physics question
Elza [17]
I think trace 1 is ac and trace 2 if dc but i’m not sure what will happen when a higher frequency is added?
7 0
3 years ago
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it
SashulF [63]

Answer:

2.4\sqrt{L} where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

gsin\theta = 9.81 sin17^o = 2.87 m/s^2

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

v^2 - v_0^2 = 2a\Delta s

where v m/s is the final velocity, v_0 = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and \Delta s = L is the distance traveled:

v^2 - 0 = 2*2.87*L

v = \sqrt{5.74L} = 2.4\sqrt{L}

6 0
3 years ago
PLEASE HURRY, WILL GIVE BRAINLIEST!!!
Brilliant_brown [7]

Answer:

1. Convection (Moving Water)

2. Radiation (Sunlight)

3. Conduction (Direct Contact)

4.  Convection or Radiation (Most Likely Convection) (Moving Air/Sunlight)

5. Convection (Moving Air)

6. Radiation (Feeling Heat)

Explanation:

See Above

3 0
2 years ago
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