1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phoenix [80]
3 years ago
12

What rule is this violating?

Chemistry
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

without being wordy, CARBON makes Only 4 and Always 4 bonds. If you want to count electrons & so on, go ahead, but in the end the

Primary Rule In Organic Chemistry is

Carbon makes 4 bonds. Check the OCTET RULE and so on to see if that gives you insight as to why, and a more complete answer. OK?

Explanation:

You might be interested in
In the fermentation of glucose (wine making), 790 mL of CO2 gas was produced at 37 ∘C and 1.00 atm . You may want to reference (
Gennadij [26K]

<u>Answer:</u> The volume of the gas when the pressure and temperature has changed is  0.811 L

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

Conversion factor used:

1 L = 1000 mL

1 atm = 760 mmHg

P_1=1.00atm=760mmHg\\V_1=790mL=0.790L\\T_1=37^oC=[37+273]K=310K\\P_2=695mmHg\\V_2=?L\\T_2=18^oC=[18+273]K=291K

Putting values in above equation, we get:

\frac{760mmHg\times 0.790L}{310K}=\frac{695mmHg\times V_2}{291K}\\\\V_2=\frac{760\times 0.790\times 291}{310\times 695}=0.811L

Hence, the volume of the gas when the pressure and temperature has changed is 0.811 L

3 0
3 years ago
How much calcium hydroxide in grams is needed to produce 1.5 l of a 0.25m solution?
Vesna [10]
The  mass    ca(Oh)2  needed  to  produce  1.5 l  of  0.25 solution  is  calculated  as follows
find  moles
 
=moles   = molarity   x  volume

moles is therefore =   1.5  x 0.25  =  0.375  moles

mass  =  moles  x  molar  mass
0.375mol  x  74.09 g/mol  =  27.78  grams
6 0
4 years ago
tyrosine kinase inhibitor binds and inhibits BTK. As a result of the experiment, you are able to elute BTK from the column, but
Sindrei [870]

Answer: It is because tyrosine kinases and BTK have similar solubilities

Explanation:

In column chromatography, components of a mixture are seperated based on their relative solubilities in two non-mixing phases.

In essence, tyrosine kinases and BTK are present in the eluate due to their similar solubility rates that arise from the similar chemical structure both possess (otherwise it would be impossible for the inhibitor meant for Tyrosine kinase to bind and also inhibits BTK)

Thus, the similar solubilities of both groups is the reason they could elute out of the column without being adsorped.

3 0
4 years ago
Gallium (Ga) consists of two naturally occurring isotopes with masses of 68.926 and 70.925 amu. (a) How many protons and neutron
pav-90 [236]

Answer:

neutrons_{Ga-69}=38\\\\neutrons_{Ga-71}=40

Explanation:

Hello!

In this case, since isotopes of the same element have the same number of protons and electrons but different atomic mass, we can compute the number of neutrons by subtracting the number of protons to the atomic mass of the isotope; thus, for Ga-69 and Ga-71 (rounded up to whole numbers), we obtain:

neutrons_{Ga-69}=69-31=38\\\\neutrons_{Ga-71}=71-31=40

Best regards!

8 0
3 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

4 0
3 years ago
Other questions:
  • PLEASE HELP MEEEE!!!!!
    7·2 answers
  • Consider the reaction cacn2 + 3 h2o → caco3 + 2 nh3 . how much nh3 is produced if 187 g of caco3 are produced? 1. 2.13 mol 2. 63
    5·1 answer
  • A 200-kg flat-bottomed boat floats in fresh water, which has a density of 1000 kg/m3. If the base of the boat is 1.42 m wide and
    14·1 answer
  • What is a mole and why do we use it
    15·1 answer
  • How many electrons are in an atom of elemental sodium?
    8·2 answers
  • Why is sodium an active metal
    12·1 answer
  • Calculate the pH of the following?
    5·1 answer
  • What forces act on a stationary bike
    12·1 answer
  • In which level of organization would the roots of a plant most likely be classified. Make sure to explain
    10·1 answer
  • What would happen to the gravity between two objects if the mass of one object decreased?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!