Cellulose and starch would be the indicator that the unknown substance is a plant.
Answer:
A flame is defined as the gaseous part of the fire which is visible to us. A flame is created due to the high exothermic reaction.
Two types of flames based on the amount of oxygen available are:
- Non-luminous or blue flame: In this type of flame the amount of oxygen is sufficiently large and it gives blue flame. For example: flame of Gas stove.
- Luminous flame: In this type of flame, the oxygen availability id not sufficient for the complete combustion and left unburnt carbon particles that forms yellow light flame. For example: kerosene lamp.
Answer:
Dissociation factor = 1.8
Explanation:
Data provided in the question:
Molecular weight of the Procaine hydrochloride = 273
Number of ions contained, n = 2
Fraction Dissociating, α = 80% = 0.8
Now,
the dissociation factor 'i' is given as:
i = 1 + α × ( n - 1 )
on substituting the respective values, we get
i = 1 + 0.8 × ( 2 - 1 )
or
i = 1 + ( 0.8 × 1 )
or
i = 1.8
Answer:
A,
C.
D.
B.
Explanation:
The front vent of a fume hood that assists and maintain proper air circulation is <u>Airfoil</u>
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The horizontal flat surface area of the fume hood where experiments are being carried out is <u>Work Surface.</u>
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The main characteristics which demonstrate and describes how substances evaporate rapidly and readily into the thin air while producing a huge amount of vapor is known as <u>Volatile</u>
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In front of the fume hood, lies the glass panel whose main purpose is to shield the user from the hazardous substance. This glass panel is known as the<u> Sash.</u>
Answer:
The change in concentration of H+ ions is -9.99×10⁻⁵
Explanation:
When pH rises, we talk about neutralization and, there is a decline in proton's concentration.
pH lower than 7 is acid
pH higher than 7 is basic
Protons are neutralized by hydroxides to make water as this:
H₃O⁺ + OH⁻ ⇄ H₂O
pH = - log [H₃O⁺]
[H₃O⁺] = 10^-pH
In conclussion: [H₃O⁺]₁ = 10⁻⁴ → 1×10⁻⁴
[H₃O⁺]₂ = 10⁻⁷ → 1×10⁻⁷
1×10⁻⁷- 1×10⁻⁴
The change in concentration of H+ ions is -9.99×10⁻⁵