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MrRa [10]
2 years ago
7

How as bohr's atomic model similar to Rutherford's model

Physics
2 answers:
zysi [14]2 years ago
6 0

Answer:

It described a nucleus surrounded by a large volume of space

Explanation:

In 1911 Rutherford, based on the results of his famous gold foil experiment, proposed that the atoms are made of positively charged and highly denser nucleus, around which the negatively charged and weightless electrons are revolving.

But he failed to provide the reason why the electrons are not continuously emitting electromagnetic radiation, since according to classical physics charged particle in circular motion emits radiation.

in 1913 Bohr improved this model by the quantization of orbits.

According to his theory electrons are revolving in stable orbits at particular radius and they emit radiation only when the move from one orbit to another.

So description of a nucleus surrounded by a large volume of space is the similarity to Rutherford’s model.

Lemur [1.5K]2 years ago
5 0

It described a nucleus surrounded by a large volume of space. ... Electrons travel around the nucleus in fixed energy levels with energies that vary from level to level. C) Electrons travel around the nucleus in fixed energy levels with equal amounts of energy.

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creativ13 [48]

Answer:

Explanation:

Deer = primary consumer

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3 years ago
Two buses are driving along parallel freeways that are 5mi apart, one heading east and the other heading west. Assuming that eac
Oksanka [162]

Answer:

101.54m/h

Explanation:

Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;

Let l be the be the distance further away at which they will meet from the current points;

l=\sqrt{13^2-5^2}=12m\\\\\frac{dl}{dt}=-(55m/h+55m/h})\\\\=-110m/h#The speed toward each other.

\frac{dh}{dt}=0, \ \ \ \ h=constant\\\\h^2+l^2=b^2\\\\2h\frac{dh}{dt}+2l\frac{dl}{dt}=2b\frac{db}{dt}\\\\2\times5\times0+2\times12\times(-110)=2\times13\frac{db}{dt}\\\\\frac{db}{dt}=-101.54m/h

Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h

4 0
2 years ago
Chord progressions that move to resting points that release tension are called
Sav [38]

Cadences.

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I really need help.
Zielflug [23.3K]
2/5 = .4
.4*100= 40%
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Answer:

Answer:

304

Explanation:Answer:

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