Consider 20 deg.C. as room temperature.
From tables,
Silver has a resistivity of 1.6*10^-8 ohm-m at 20 deg.C, and it increases by 0.0038 ohm-m per deg.K increase.
Therefore if the temperature rise above 20 deg.C is T, then silver will have resistivity of
1.6*10^-8(1 + 0.0038T) ohm-m
At room temperature, the resistivity of tungsten (from tables) is 5.6*10^-8.
The resistivity of silver will be 4 times that of tungsten (at room temperature) when
1.6*10^-8(1 + 0.0038T) = 4*5.6*10^-8
1 + 0.0038T = 14
T = 13/.0038 = 3421 deg.K approx
Answer: 20 + 3421 = 3441 °C
Answer:
this pdf should help you out
Explanation:
Answer: 0.42 Amperes
Explanation:
Given that:
Current, I = ?
Electric charge Q = 100 coulomb
Time, T = 4.0 minutes
(The SI unit of time is seconds. so, convert 4.0 minutes to seconds)
If 1 minute = 60 seconds
4.0 minutes = 4.0 x 60 = 240 seconds
Since electric charge, Q = current x time
i.e Q = I x T
100 coulomb = I x 240 seconds
I = 100 coulomb / 240 seconds
I = 0.4167 Amperes (round to the nearest hundredth which is 0.42 amperes)
Thus, 0.42 Amperes of current flows in the circuit.
To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.
Planet gravitational force
Distance between planet and star
Gravitational force is
Applying the new distance,
Replacing with the previous force,
Replacing our values
Therefore the magnitude of the force on the star due to the planet is 
