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Kamila [148]
3 years ago
10

A snail crawls 300 cm in 1 hour. Calculate the snail's speed in each of the following units. A) cm/h B) cm/min C) m/h

Physics
1 answer:
Crazy boy [7]3 years ago
7 0
A) 300cm/h
B)1 hr=60 min
300/60=5
5cm/min
C)1m=100cm
300/100=3
3m/h
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Alice drops a rock to a well. She hears the splash of the rock 4.1s later. The speed of sound is 340m/s. How deep is the well
Maksim231197 [3]

Answer:

697 m

Explanation:

From the question above,

Note: Alice hears the splash of the rock in the well through the help of echo.

Applying,

v = 2x/t........................ Equation 1

Where v = speed of sound, x = depth of the well, t = time.

make x the subject of the formula in equation 1

x = vt/2................... Equation 2.

Given: v = 340 m/s, t = 4.1 s

Substitute these values into equation 2

x = 340(4.1)/2

x = 697 m.

3 0
3 years ago
The concentration of an acid or base refers to how completely it dissociates in
Novosadov [1.4K]

Answer:

False

Explanation:

The Concentration of Acid or Base is the ph of the solution.

6 0
3 years ago
A car is moving in the positive direction along a straight highway and accelerates at a constant rate while going from point A t
rusak2 [61]

Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

The velocity of the car is:

v(t) = v0 + at

Where v0 is the initial speed and a is the constant acceleration.

Let's find the average speed. This is given integrating the velocity from 0 to T and dividing by T:

v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

v_ave = v0+a(T/2)

We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

x(t) = x_A + v_0 t + \frac{1}{2}at^2

Where x_A is the position of point A. Therefore, the car will be at:

<u><em>x(T/2) = x_A + v_0 (T/2) + (1/8)aT^2</em></u>

8 0
2 years ago
¿Cuál es la magnitud y dirección de la aceleración de los cuerpos en caída libre en el planeta Tierra?
Tatiana [17]

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La dirección es hacia el centro de la Tierra. (Llamamos a esa dirección "abajo").

6 0
3 years ago
a baseball is hit 3 feet above ground level at 100 feet per second and at an angle of 45 with respect to the ground. (g=32 feet/
LiRa [457]

Answer:

hmax=81ft

Explanation:

Maximum height of the object is the highest vertical position along its trajectory.

The vertical velocity is equal to 0 (Vy = 0)

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we isolate th (needed to reach the maximum height hmax)

th = \frac{v_{0}*sin(\alpha)}{g}

The formula describing vertical distance is:

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So, given y = hmax and t = th, we can join those two equations together:

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if we launch a projectile from some initial height h all you need to do is add this initial elevation

hmax =h+Vo^{2}*sin(\alpha)^{2}/(2*g)

hmax =3+100^{2}*sin(45)^{2}/(2 * 32)=81 ft

6 0
3 years ago
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