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adell [148]
3 years ago
13

How much heat is evolved when 22.5 grams of a food sample changes the temperature of 0.42 kg of water by 4.4 degree C. Assume sp

ecific heat to be 4.18 J/g/C
Chemistry
1 answer:
irakobra [83]3 years ago
3 0
The answer is C. Assume specific heat to be 4.18 J/g/C
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What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?
faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

(a)  ml=3

(b ) ml= −4

a) -278 x 10^{-23}J/T

b) 3.71 x 10^{-23}J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x 10^{-23}J/T

b) ml= 3

Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x 10^{-23}J/T

3 0
3 years ago
What is the mass of 0.250 moles of tungsten
andrey2020 [161]
X it by the molar mass of tungsten
3 0
2 years ago
How is heat transfer through space
sladkih [1.3K]
Well, the sun is in space, right? It has to be able to transfer heat through space, or how would it get to us? Radiation helps transfer heat.
7 0
3 years ago
What is the percent yield if 248.7 g of Cu is produced when 87 g of Al reacts with an excess
valkas [14]

Answer:

2.09 g Cu

Explanation:

First, we have to balance the equation:

3Al(s) + 3CuSO4(aq) = Al2(SO4)3(aq) + 3Cu(s)

Then we have to change grams of Al to mol:

1 mol Al = 26.98 g

1.37 g Al x (1 mol/26.98 g) = 0.051 mol

Then, we use the balanced equation to find the mol of Cu produced:

According to the equation:

3 mol Al produces 3 mol of Cu

3 mol Al = 3 mol Cu

So:

0.051 mol Al x (3 mol Cu/3 mol Al) = 0.051 mol Cu

This mol value is the theoric yield of the reaction.

Remember the equation for yield percent:

%Y = (Y real / Y theoric) x 100

Y theoric = 0.051 mol Cu

% Y = 67.4%

Let's replace these values on the equation and then fin Y real.

67.4 % = (Y real / 0.051) x 100

Y real = 0.033 mol Cu

So the real produced mol is 0.033 mol Cu.

Let's change these moles to grams:

1 mol Cu = 63.55 g

0.033 mol Cu x ( 63.55 g Cu/ 1 mol Cu) = 2.09 g Cu

If you want, watch the image attached is more clear the

mathematical procedure

Explanation:

6 0
2 years ago
Is freezing depression dependent on having a salt solute, or can non-ionic particles also have an affect on the freezing point o
luda_lava [24]

Answer:

It is not dependent on the salt solute at all but the solute does have an affect.

Explanation:

in the equation you maybe aware of the I factor which represents the ions present in the solution. a non ionic will always have a I value of 1 a ionic can be 2 like in NaCl. What this means that all non ionic will lower the temperature  depression but ionics will have a greater affect because for example salt breaks into Na and Cl will essentially hae more impurities than glucose which doesnt dissociate and will have a I value of 1

5 0
3 years ago
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