What is name of: <br>1.Ca(H2PO4)2, <br>2.Fe(HSO4)2, <br>3.(CaOH)2SO4<br>4.Al(OH)Cl2

When equal volumes of 0.5 M HCl and 0.5 M Ca(OH)2 are mixed, the resulting solution is

Mademuasel [1]

The concentration of mixed solution = 0.5 M

<h3> Further explanation </h3>

Given

0.5 M HCl

0.5 M Ca(OH)₂

Required

The concentration

Solution

Molarity from 2 solutions :

Vm Mm = V₁. M₁ + V₂. M₂

m = mixed solution

V = volume

M = molarity

V = mixed volume

1 = solution 1

2 = solution 2

Vm = V₁+V₂

Equal volumes⇒V₁=V₂, and Vm = 2V, then equation becomes :

2V.Mm = V(M₁+M₂)

2V.Mm = V(0.5+0.5)

Mm=0.5 M

8 0

2 years ago

Meteorologists use weather balloons to carry weather instruments high into the atmosphere. When it is first released at Earth’s

inessss [21]

The pressure of the gas used in the weather balloon increases to expand the balloon.

Explanation:

Weather balloons contain the boxes where the weather measurement instruments are present that is attached to the large balloon.
Weather balloon uses gases like Hydrogen or Helium. When the weather balloon rises to the atmosphere, the air pressure decreases. This leads to the increase in the pressure of hydrogen or Helium gas used in the weather balloon. This expands the balloon.
The gas particles hits the balloon container and generates the pressure. The increase of pressure thus helps the weather balloon to move in a constant speed through the atmosphere.

8 0

3 years ago

This is the chemical formula for talc Mg3(Si2O5)2(OH)2(the main ingredient in talcum powder):

Elena-2011 [213]

Answer:

0.022 mol O

Explanation:

Mg3(Si2O5)2(OH)2

We can see that 1 mol of this substance has 3 mol of Mg.

Oxygen altogether is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12

So, 1 mol of this substance has 12 mol oxygen.

So, 1 mol of this substance contains 3 mol Mg and 12 mol O, or

ratio Mg : O = 3 : 12 = 1 : 4

1 mol Mg ----- 4 mol O

0.055 mol Mg ---x mol O

x = 0.055*4/1 = 0.220 mol O

8 0

3 years ago

A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i

Alexeev081 [22]

Answer:

$MM_{acid}=140.1g/mol$

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

$n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}$

Thus, solving for the moles of the acid, we obtain:

$n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol$

Then, by using the mass of the acid, we compute its molar mass:

$MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol$

Regards.

7 0

2 years ago

Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 4.0 moles of N2 react with

Sphinxa [80]

Answer : The work done is, $1.98\times 10^4J$

Explanation :

The given balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

When 4 moles of $N_2$ react with 12 moles of $H_2$ then it gives 8 moles of $NH_3$

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of $N_2$ + Moles of $H_2$

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of $NH_3$

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K$

$V=195.7L$

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V$

where,

w = work done

p = pressure of the gas = 1.0 atm

$\Delta V$ = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

$w=-p\Delta V$

$w=-(1.0atm)\times (-195.7L)$

$w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J$

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, $1.98\times 10^4J$

6 0

3 years ago

What is name of: 1.Ca(H2PO4)2, 2.Fe(HSO4)2, 3.(CaOH)2SO44.Al(OH)Cl2​

What is name of: 1.Ca(H2PO4)2, 2.Fe(HSO4)2, 3.(CaOH)2SO44.Al(OH)Cl2