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Ganezh [65]
3 years ago
11

How many moles of NaOH must be dissolved in 1.00 L of water to make NaOH (aq) with a pH of 12.2?

Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

1.58 102 mol

Explanation:

I just looked it up on Quizlet.

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A person weighed 15 pennies on a balance and recorded the following masses:
Artist 52 [7]

Answer:

A)  yes

B) The average mass of 12 pennies should be expressed as

( 3.131 + 3.129 + -------- X12 ) g /  12

where X12 = is the mass of the 12th penny

Explanation:

A) I think the the Bureau of Mint changed the way it made pennies because from the experiment and observation carried out on 15 different pennies it can be seen that they had different weights and this difference is associated with the period/time of production of the different pennies,

B ) The average mass of any object should be expressed in the si unit of mass and not having ($) sign attached to the value instead it should be expressed in grams or kilograms (s.i unit of mass )

The average mass of 12 pennies should be expressed as

( 3.131 + 3.129 + -------- X12 ) g /  12

where X12 = is the mass of the 12th penny

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3 years ago
If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the
uysha [10]

Answer:

2.01 M

Explanation:

Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)

The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

36.2g \times \frac{1mol}{60.05g} = 0.603mol

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

300mL \times \frac{1L}{1000mL} = 0.300L

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

M = \frac{0.603mol}{0.300L} = 2.01 M

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