Answer: V2 = 35.54L
Explanation:
Applying
P1= 67.4, V1= 85, T1= 245, P2= 179.6, V2= ?,. T2=273
P1V1/ T1= P2V2/T2
Substitute and simplify
(67.4*85)/245 = (179.6*V2)/273
V2= 35.54L
Answer: Time required to deposit an even layer of gold with given thickness is
sec.
Explanation:
The given data is as follows.
Surface area = 49.8
,
Density of gold = 19.3
,
Current = 3.15 A, thickness of gold layer = 
It is known that relation between volume, area and thickness is as follows.
V = Surface area × Thickness
= 
= 0.05988 
Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

=
sec
Thus, we can conclude that time required to deposit an even layer of gold with given thickness is
sec.
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The answer is C: How long does it take distilled water to evaporate from a 5” diameter container?