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Ipatiy [6.2K]
3 years ago
14

9. The formular for finding the area

Chemistry
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

D. length × width

Explanation:

eg. 30 cm(length) × 20cm(width) = 600cm²

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The standard enthalpy of formation of Ca2+ (g) (∆H = 1934 kJ/mol)
Alex73 [517]

Answer:

see explanation

Explanation:

The process of ionization to produce cations is endothermic. For formation of Ca⁺² two ionization steps need be illustrated as follows...

1st ionization step: Ca° + 590Kj => Ca⁺ + e⁻

2nd ionization step: Ca⁺ + 1151Kj => Ca⁺² + e⁻

__________________________________-

Net Ionization Rxn: Ca° + 1741Kj => Ca⁺² + 2e⁻

6 0
3 years ago
How many grams of PbBr2 will precipitate when excess CuBr2 solution is added to 77.0 mL of 0.595 M Pb(NO3)2 solution?Pb(NO3)2(aq
Alexxx [7]

Answer:

16.89g of PbBr2

Explanation:

First, let us calculate the number of mole of Pb(NO3)2. This is illustrated below:

Molarity of Pb(NO3)2 = 0.595M

Volume = 77mL = 77/1000 = 0.077L

Mole =?

Molarity = mole/Volume

Mole = Molarity x Volume

Mole of Pb(NO3)2 = 0.595x0.077

Mole of Pb(NO3)2 = 0.046mol

Convert 0.046mol of Pb(NO3)2 to grams as shown below:

Molar Mass of Pb(NO3)2 =

207 + 2[ 14 + (16x3)]

= 207 + 2[14 + 48]

= 207 + 2[62] = 207 +124 = 331g/mol

Mass of Pb(NO3)2 = number of mole x molar Mass = 0.046 x 331 = 15.23g

Molar Mass of PbBr2 = 207 + (2x80) = 207 + 160 = 367g/mol

Equation for the reaction is given below:

Pb(NO3)2 + CuBr2 —> PbBr2 + Cu(NO3)2

From the equation above,

331g of Pb(NO3)2 precipitated 367g of PbBr2

Therefore, 15.23g of Pb(NO3)2 will precipitate = (15.23x367)/331 = 16.89g of PbBr2

8 0
3 years ago
Basilosaurus cetoides was a large mammal that existed 35 million years ago. It was 20 m long and had a large skull, incompletely
Korvikt [17]

Answer: hey so I’m taking the same test as you right now. I’m on that question and I searched it up and came on here. Would you mind telling me the answer?

Explanation:

5 0
3 years ago
Explain what a chromosome is in your own words.
Alex787 [66]
It’s a structure of nucleic acids and protein that can be found in the nucleus; it carries genetic information through genes
7 0
3 years ago
Read 2 more answers
1. How many molecules are in 240g of sulfuric acid?
Soloha48 [4]

Answer:

14.8 × 10²³ molecules

Explanation:

Given data:

Mass of sulfuric acid = 240 g

Number of molecules = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Number of moles of sulfuric acid

<em>Number of moles = mass/ molar mass</em>

Number of moles =  240 g/ 98 g/mol

Number of moles = 2.45 mol

Number of molecules:

1 mole = 6.022 × 10²³ molecules

2.45 × 6.022 × 10²³ molecules

14.8 × 10²³ molecules

3 0
3 years ago
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