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Colt1911 [192]
3 years ago
11

What distance will a car cover accelerating from 12 m/s to 26 m/s in 14 sec?

Physics
1 answer:
Sladkaya [172]3 years ago
5 0
A = Vf - Vi / t

A = 26m/s - 12 m/s / 14 s

A = 14 m/s / 14 s

A = 1 m
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A ball is thrown straight up with an initial speed of 36 m/s . Part A How much time does it take for the ball to reach the top o
nevsk [136]

Answer:3.67 s

Explanation:

Given

Ball is thrown with an initial velocity of u=36\ m/s

As the ball moves upward it experience a declaration due to gravity which will slow down the ball

using

v=u+at

where v=final velocity

u=initial velocity

a=acceleration

t=time

Here v=0

0=36-9.8\times t

t=\frac{36}{9.8}

t=3.67\ s

8 0
3 years ago
___________ is the gradual increase in the overall temperature of the earth’s atmosphere generally attributed to the greenhouse
victus00 [196]
Global Warming 

hope it helps you!
8 0
3 years ago
Read 2 more answers
A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii. If the three of them are released simultaneou
Roman55 [17]

Answer:

The solid sphere will reach the bottom first.

Explanation:

In order to develop this problem and give it a correct solution, it is necessary to collect the concepts related to energy conservation. To apply this concept, we first highlight the importance of conserving energy so we will match the final and initial energies. Once this value has been obtained, we will concentrate on finding the speed, and solving what is related to the Inertia.

In this way we know that,

\Delta KE = - \Delta PE

KE_t + KE_r = mgh

We know as well that the lineal and angular energy are given by,

KE_r = \frac{1}{2}I\omega^2

And the tangential kinetic energy as

KE_t = \frac{1}{2} mv^2

Where\omega = \frac{v}{R}

Replacing

\frac{1}{2}mv^2 + \frac{1}{2}I\frac{v}{R} = mgh

Re-arrange for v,

v=\sqrt{\frac{2mgh}{m+I/R^2}}

We have here three different objects: solid cylinder, hollow pipe and solid sphere. We need the moment inertia of this objects and replace in the previous equation found, then,

For hollow pipe:

I_{hp}=mR^2

v_{hp}=\sqrt{\frac{2mgh}{m+(mR^2)/R^2}}

v_{hp}=\sqrt{\frac{2mgh}{m+m)}

v_{hp}=\sqrt{gh}

For solid cylinder:

I_{sc}=\frac{1}{2}mR^2

v_{sc}=\sqrt{\frac{2mgh}{m+(1/2mR^2)/R^2}}

v_{sc}=\sqrt{\frac{2mgh}{m+1/2m}}

v_{sc}=\sqrt{\frac{3}{4}gh}

For solid sphere,

I_{ss}=\frac{2}{5}mR^2

v_{ss}=\sqrt{\frac{2mgh}{m+(2/5mR^2)/R^2}}

v_{ss}=\sqrt{\frac{2mgh}{m+2/5m}}

v_{ss}=\sqrt{\frac{10}{7}gh}

Then comparing the speed of the three objects we have:

v_{hp}

\sqrt{gh}

3 0
4 years ago
Which factor (s) have the most affect a person’s vital capacity? Rank in order from MOST effect (1) to least effect (5)
jenyasd209 [6]

The factors that affect vital capacity are :

  1. Age
  2. Sex
  3. Height
  4. Body mass
  5. Ethnicity

Explanation:

Vital capacity is the maximum amount of air that a person can exhale once he has filled his lungs with maximum air. So, it is like maximum exhalation after maximum inhalation by a person.

Vital capacity is also equal to Forced Vital Capacity.

Lung usually have their maximum capacity in early adult days and this capacity reduces as the person grows older. So age is the prime factor in this.

A female with same age and height as that of male will have 10-12% less vital capacity than him. So sex is another reason which determines vital capacity.

Person with more height has more vital capacity. This is because lungs capacity is closely related to the third power of person's height.

Person suffering from obesity will have compressed diaphragm, lung and chest cavity , so their vital capacity will be less. So we can say body mass affects vital capacity.

Last factor, ethnicity, is yet to be understood clearly as there is not much evidence of this.

3 0
3 years ago
An alpha particle consists of two protons and two neutrons with a mass of 6.64 x 1027 kg and charge 3.2 x 10-19 C. If two of the
Dafna11 [192]

Answer:  ratio = 3.14 × 10³⁵

Explanation:

From Newtons law of Universal Gravitation;

Every object in the universe is attracted to every other object

F = (Gm₁m₂)/r²

G = 6.67 X 10⁻¹¹ N-m²/kg²

M₁= mass of one object

M₂= mass of second object

r = distance from center of objects

q = charge = 3.2 x 10⁻¹⁹C.

  • Calculating the gravitational force;

Fg = (Gm₁m₂)/r² = (Gm²)/r²

which is = (6.67×10⁻¹¹ × (6.64×10⁻²⁷)²) / r²

= (2.94 × 10⁻⁶³) / r²

  • Calculating the electric force;

Fe = (Kq₁q₂) / r² = K q² / r² = (9×10⁹ × (3.2 × 10⁻¹⁹)² / r²

Fe = 9.22 × 10⁻²⁸ / r²

comparing the ratio of both forces we have;

Fe/Fg = (9.22×10⁻²⁸/r²) ÷ (2.94×10⁻⁶³/r²)

r² cancels from the above expression, which gives;

ratio as 3.14 × 10³⁵

8 0
3 years ago
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