Answer:
Explanation:
Given that, .
The half-life of a radioactive element is
t½ = 1 hr.
At the first hour, the radioactive element has 40 counts/minute
After 4 hours it has 5 counts/minute
So,
We want to filled the table.
0 hours, I.e at the start
40 counts/mins × 2 = 80 counts / mis
First half-life (first hour) is
40 counts/mins
Second half-life (second hour)
40 counts/mins × ½ = 20 counts/mins
Third half-life (third hour)
40 counts/mins × ¼ = 10 counts / mins
Fourth half life (fourth hour)
40 counts/mins × ⅛ = 5 counts / mins
So, the table is
Time........................Geiger Counter Rate
0 hours.................... 80 counts / minutes
1 hour........................ 40 counts / minutes
2 hours..................... 20 counts / minutes
3 hours..................... 10counts / minutes
4 hours...................... 5 counts / minute
