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adelina 88 [10]
2 years ago
14

You illuminate the surface of some metal with green laser and observe the photocurrent. If you decrease the intensity of laser,

the stopping potential will
Physics
1 answer:
gregori [183]2 years ago
7 0

Remain the same.

Explanation:

The kinetic energy of the ejected electrons, and thus the resulting photocurrent, does not depend on the intensity of the incident radiation. Instead, it depends on the frequency. So since the stopping potential is used to reduce the photocurrent to zero and the photocurrent does not depend on the intensity, the stopping potential remains the same.

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A stone is dropped from rest from the top of a building. It takes Δt = 2.2 s for it to reach the ground.
NeTakaya

Answer:

Value of magnitude of acceleration will be 9.8m/sec^2

Explanation:

It is given that when a stone is dropped it takes 2.2 sec to reach the ground

(a) As the stone is dropped from the top of building

So its initial velocity u_i will be 0 m /sec

(b) As the stone is free falling and there is no external force applied on it so its acceleration will be equal to acceleration due to gravity

So value of magnitude of acceleration will be equal to 9.8m/sec^2

6 0
3 years ago
Can a ratio be expressed as a percentage
cupoosta [38]
Yes, ratio can be expressed in percentage.
7 0
3 years ago
what voltage would produce a current of 100A through an aluminum wire that has a resistance of 3.44x10^-4 ohm?
Serga [27]
Voltage = Current x Resistance 
<span>Voltage(?) = 100 x 1.98x10^-4 ohms </span>

<span>Voltage = Current x Resistance </span>
<span>Voltage(?) = 250 x 2.09x10^-4 ohms </span>

<span>Voltage = Current x Resistance </span>
<span>Voltage(?) = 100 x 3.44x10^-4 ohms</span>
7 0
3 years ago
A marble rolling at a speed of 2 meters per second falls off the end of a 1-meter high table. How long will the marble be in the
irga5000 [103]

<span>t^2 = 1/4.9 </span>
<span>t = 0.45 sec 
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8 0
3 years ago
Ajoba and Prav drive to work. Ajoba drives 45 miles in 2.5 hours. Prav drives 74 km in 1 hour 15 min. Work out the difference be
Serggg [28]

Explanation:

We have,

Ajoba and Prav drive to work. Ajoba drives 45 miles in 2.5 hours. Prav drives 74 km in 1 hour 15 min.

1 mile = 1.6 km

45 miles = 72.42 km

74 miles = 119.0 km

1 hour 15 min means 1.25 hours

Average speed of Ajoba is :

v_1=\dfrac{72.42 }{2.5}=28.96\ km/h

Average speed of Prav,

v_2=\dfrac{119}{1.25}=95.2\ km/h

Difference in average speed of Ajoba and Prav is :

v=v_2-v_1\\\\v=v_2-v_1\\\\v=95.2-28.96\\\\v=66.24\ km/h

So, the difference in average speed of Ajoba and Prav is 66.24 km/h.

7 0
3 years ago
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