1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
adelina 88 [10]
2 years ago
14

You illuminate the surface of some metal with green laser and observe the photocurrent. If you decrease the intensity of laser,

the stopping potential will
Physics
1 answer:
gregori [183]2 years ago
7 0

Remain the same.

Explanation:

The kinetic energy of the ejected electrons, and thus the resulting photocurrent, does not depend on the intensity of the incident radiation. Instead, it depends on the frequency. So since the stopping potential is used to reduce the photocurrent to zero and the photocurrent does not depend on the intensity, the stopping potential remains the same.

You might be interested in
In a thermostat, what property of the bimetallic coil allows it to contract and expand? The two metals absorb different amounts
Reika [66]
Hello!

In a thermostat, the property of the bimetallic coil that allows it to contract and expand is that The two metals absorb different amounts of thermal energy. 

This bimetallic coil is used to transform thermal energy into mechanical movement. Two metals with different thermal expansivity are joined together parallelly and the changes of temperature cause bending in different directions depending on if the temperature is rising or descending. 

The differences in the thermal energy absorption of the two metals are the basis for the mechanism of this device. 
3 0
4 years ago
Read 2 more answers
A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is
Tasya [4]

Answer:

C) T

Explanation:

M = Mass attached to an ideal spring

A = Amplitude of the motion

T = Time period of oscillation

k = Spring constant of the spring

A = Amplitude of the motion

Time period of oscillation of the mass attached to the spring is given as

T = 2\pi \sqrt{\frac{M}{k} }

So we see that the time period does not depend on the amplitude. hence the period of oscillation remains the same.

8 0
4 years ago
(1 point) A mass m=4kg is attached to both a spring with spring constant k=577N/m and a dash-pot with damping constant c=4N⋅s/m
sasho [114]

Answer:

The function is x = e^(-t/2) * (0.792*sin12t + 5cos12t)

Explanation:

we have to:

m = mass = 4 kg

k = spring constant = 577 N/m

c = damping constant = 4 N*s/m

The differential equation of motion is equal to:

m(d^2x/dt^2) + c(dx/dt) + k*x = 0

Replacing values:

4(d^2x/dt^2) + 4(dx/dt) + 577*x = 0

Thus, we have:

4*x^2 + 4*x + 577 = 0

we will use the quadratic equation to solve the expression:

x = (-4 ± (4^2 - (4*4*577))^1/2)/(2*4) = (-4 ± (-9216))/8 = (1/2)  ± 12i

The solution is equal to:

x = e^(1/2) * (c1*sin12t + c2*cos12t)

x´ = (-1/2)*e^(1/2) * (c1*sin12t + c2*cos12t) + e^(-t/2) * (12*c1*cos12t - 12*c2*sin12t)

We have the follow:

x(0) = 5

e^0(0*c1 + c2) = 5

c2 = 5

x´(0) = 7

(-1/2)*e^0 * (0*c1 + c2) + e^0 * (12*c1 - 0*c2) = 7

(-1/2)*(5) + 12*c1 = 7

Clearing c1:

c1 = 0.792

The function is equal to:

x = e^(-t/2) * (0.792*sin12t + 5cos12t)

8 0
3 years ago
Just a test for my internet :)
Talja [164]

Answer:

Okay

Explanation:

3 0
2 years ago
A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir
Fantom [35]

Answer:

linear charge density = -9.495 × 10^{-34} C/m

Explanation:

given data

revolutions per second = 1.80 × 10^{6}

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

so

- q × E = m × w² × r     ..................1

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}r} q =  m × w² × r   ............2

and w = \frac{2*\pi}{T}  

w = \frac{d\theta }{dt}

w = 1.80 × 10^{6} × \frac{2*\pi}{1}

w = 11304000 rad/s

so here from equation 2

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}{0.012} 1.80 × 10^{6} =  1.672 × 10^{-27} × 11304000² × 0.0120  

linear charge density = -9.495 × 10^{-34} C/m

8 0
3 years ago
Other questions:
  • How do noise canceling headphones work?
    11·2 answers
  • What is the differnece in shades
    5·1 answer
  • 1. What is the SI unit of emf?
    8·2 answers
  • At 350 K what is the approximate volume? What will be the approximate volume when the temp is 900 K?
    8·1 answer
  • Does exists the friction force in space?If yes,tell an full example
    8·1 answer
  • The above Free Body Diagram represents the motion of a toy car across a floor from left to right. The weight of the .5 kg car is
    12·1 answer
  • Hurricanes are formed due to
    14·2 answers
  • Which quantity is represented by the area under a force-time graph?
    9·1 answer
  • A merry-go-round a.k.a "the spinny thing" is rotating at 15 RPM, and has a radius of 1.75 m
    6·1 answer
  • Newton’s second law of motion says when a is applied to a it causes it to.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!