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Gala2k [10]
3 years ago
10

if another car is following you what is likely the best action you can take to avoid an animal that runs out into the path of yo

ur car
Physics
2 answers:
Zielflug [23.3K]3 years ago
4 0

Keep your lane position, and sound your horn while braking in a controlled manner. Sudden panic stops are not a good idea, as they could spook the animal, causing it to suddenly dart into the path of another vehicle.



Oduvanchick [21]3 years ago
3 0

DO NOT SLAM ON THE BRAKE AND DO NOT PANIC. Slamming on your brakes will cause you car to skid. Swerving is not the best option as you could lose control of the car and crash. So, slowing down and not panicking will leave you with the fewest injuries on your body. Your vehicle could be affecting depending on the animal. If you hit an animal, put your hazards on a call 911.

Your life always comes before an animal.

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Energy that is transferred from a warmer object to a cooler object is called
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Heat

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A 50 kg runner runs up a flight of stairs. The runner starts out covering 3 steps every second. At the end the runner stops. Thi
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To solve the problem it is necessary to take into account the concepts of kinematic equations of motion and the work done by a body.

In the case of work, we know that it is defined by,

W = F * d

Where,

F= Force

d = Distance

The distance in this case is a composition between number of steps and the height. Then,

d=h*N, for h as the height of each step and N number of steps.

On the other hand we have the speed changes, depending on the displacement and acceleration (omitting time)

V_f^2-V_i^2 = 2a\Delta X

Where,

V_f = Final velocity

V_i = Initial Velocity

a = Acceleration

\Delta X = Displacement

PART A) For the particular case of work we know then that,

W = F*d

W = m*g*(h*N)

W = 50*9.8*(0.3*30)

W = 4.41kJ

Therefore the Work to do that activity is 4.41kJ

PART B) To find the acceleration (from which we can later find the time) we start from the previously given equation,

V_f^2-V_i^2 = 2a\Delta X

Here,

V_i = \frac{0.3*3}{1} = 0.90m/s\rightarrow3 steps in one second

v_f = 0

Replacing,

V_f^2-V_i^2 = 2a\Delta X

0-0.9^2=2a(30*0.3)

Re-arrange for a,

a = -\frac{0.9^2}{2*30*0.3}

a = -45*10^{-3}m/s^2

At this point we can calculate the time, which is,

t = \frac{\Delta V}{a}

t = \frac{0-0.9}{-45*10^{-3}}

t = 20s

With time and work we can finally calculate the power

P = \frac{W}{t} = \frac{4.41}{20}

P = 0.2205kW

6 0
3 years ago
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