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Gala2k [10]
3 years ago
10

if another car is following you what is likely the best action you can take to avoid an animal that runs out into the path of yo

ur car
Physics
2 answers:
Zielflug [23.3K]3 years ago
4 0

Keep your lane position, and sound your horn while braking in a controlled manner. Sudden panic stops are not a good idea, as they could spook the animal, causing it to suddenly dart into the path of another vehicle.



Oduvanchick [21]3 years ago
3 0

DO NOT SLAM ON THE BRAKE AND DO NOT PANIC. Slamming on your brakes will cause you car to skid. Swerving is not the best option as you could lose control of the car and crash. So, slowing down and not panicking will leave you with the fewest injuries on your body. Your vehicle could be affecting depending on the animal. If you hit an animal, put your hazards on a call 911.

Your life always comes before an animal.

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For an object moving with constant negative acceleration, draw the following:
Tcecarenko [31]

Answer:

Kindly find the graphs attached

Explanation:

For figure 1: There is a steady increase in the position of the object as time increases. This is because despite the negative acceleration (deceleration), the object continues to move and cover more ground as time goes by.

<em>The straight line graph is observed because the acceleration is constant  and not varying.</em>

For Figure 2: The graph of velocity vs time will have an inverted nature. This is because since the object is decelerating, it is reducing in its velocity as time goes by (increases). <em>This is also in a straight line since the deceleration is constant.</em>

3 0
3 years ago
A flashlight bulb is connected to a square loop of wire that measures cm on a side as shown in the figure below. assume the bulb
LUCKY_DIMON [66]
Mmmmmmmm Ф↓⇄㏑㏒,,⇆↑aaaaaaa
4 0
3 years ago
The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which
emmainna [20.7K]

Answer:

Explanation:

A ) angular velocity ω = 2π / T

= 2 x 3.14 / 60

= .10467 rad / s

linear velocity v = ω R

=  .10467 x 50

= 5.23 m / s

centripetal force = m v² / R

= mg v² / gR

= 834 x 5.23² / 9.8 x 50

= 46.55 N

B )

apparent weight

= mg - centripetal force

= 834 - 46.55

= 787.45 N

C ) apparent weight

= mg + centripetal force

= 834 + 46.55

= 880.55 N.

D )

For apparent weight to be zero

centripetal force = mg

mg = mv² / R

v² = gR

= 9.8 x 50

= 490

v = 22.13 m /s

time period of revolution

= 2π R /v

2 x 3.14 x 50 / 22.13

= 14.19 s  

8 0
3 years ago
A 32.5 g cube of aluminum initially at 45.8 °C is submerged into 105.3 g of water at 15.4 °C. What is the final temperature of b
lakkis [162]

Answer:

T = 17.26 ^oC

Explanation:

At thermal equilibrium we have heat given by aluminium must be equal to the heat absorbed by the water

so we will have

Q_1 = Q_2

m_1s_1\Delta T_1 = m_2s_2\Delta T_2

so we will have

32.5(900)(45.8 - T) = 105.3(4186)(T - 15.4)

so we have

(45.8 - T) = 15.1(T - 15.4)

so we have

16.1 T = 277.87

T = 17.26 ^oC

6 0
3 years ago
How much potential energy does a 50-N box have when lifted at a height of 1.5M?
nikitadnepr [17]

The correct answer is: Option (A) 75 J

Explanation:

First, be careful with the units here. As you can see it is mentioned that there is a 50N box. It means that the weight (<em>mg</em>) of the box is given as the unit is <em>Newton</em>, not its mass (which is in kg).

As,

Potential-energy = mass * acceleration-due-to-gravity * height

PE = m*g*h --- (A)


In equation (A), mg is actually the weight of the box, which is given.

mg = 50N

h = height = 1.5m

Plug the values in equation (A):

PE = 50 * 1.5  = <em>75 J (Option A)</em>

3 0
3 years ago
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