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Arlecino [84]
3 years ago
8

The pKa of lactic acid is 3.9. A lactate buffer will be useful from pH values ________. The pKa of lactic acid is 3.9. A lactate

buffer will be useful from pH values ________. 3.0 through 4.5 3.8 through 4.0 2.9 through 4.9 3.5 through 4.4
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

Explanation:

The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.  

This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since  buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .

From the Henderson-Hasselbach equation we have that

pH = pKa + log [A⁻]/[HA]

thus

0.1 ≤  [A⁻]/[HA] ≤ 10

Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.

Now we are equipped to answer our question:

pH range = 3.9 +/- 1 = 2.9 through 4.9

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Determine the frequency of radiation whose wavelength is 7.67 x 10^-7 cm. Then, determine the amount of energy in the radiation.
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Answer:

They frequency = 3.9 * 10^16 Hz

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Explanation:

Step 1: Data given

wavelength is 7.67 * 10^-7 cm

Step 2: Calculate the frequency

f = c / λ

⇒ with  λ = the wavelength in nm = 7.67 nm

⇒ with c = the speed of light  = 3.00 * 10^8 m/s

⇒ f = the frequency = TO BE DETERMINED

f = (3.00 * 10^8 m/s) / 7.67 * 10^-9 m

f = 3.9 * 10 ^16 /s = 3.9 * 10^16 Hz

They frequency is 3.9 * 10^16 Hz

Step 3: Calculate the amount of energy

E  =  h *f

⇒ with E = the amount of energy (in joule)

⇒ h = Planck's constant =  6.626  *10^-34 J*s

⇒ with f = the frequency

E =  6.626  *10^-34 J*s * 3.9 * 10^16 Hz

E = 2.58 *10^-17 J

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If 10 g of NaOH is diluted to 500 ml with water then  the concentration expressed in percent is 0.5 mol/L .

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Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.  

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