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igomit [66]
2 years ago
7

If two kids kick the ball at the same time what is the motion on the ball will do?​

Chemistry
1 answer:
Artyom0805 [142]2 years ago
7 0

Explanation:

I think your correct it's A!!

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Decide which element probably forms a compound with chlorine that has a chemical formula most and least similar to the chemical
Degger [83]

Answer:

Most similar - Lithium

Least similar - Phosphorus

Explanation:

Rubidium is an element in group 1A of the periodic table. It is a metal and forms an ionic compound with chlorine. The formula of the compound is RbCl.

If we look at the options, Lithium is also a group 1A element and forms an ionic compound with chlorine having the formula LiCl which is very much similar to RbCl chemically.

Phosphorus is a nonmetal. Its compounds with chlorine, PCl3 and PCl5 are covalent and does not resemble RbCl in any way.

8 0
3 years ago
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
const2013 [10]

Answer:

\boxed{\text{47.4 g}}

Explanation:

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:    17.03   32.00                 18.02  

           4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

m/g:     70.1      70.1

Step 1. Calculate the moles of each reactant

\text{Moles of CO } = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{17.03 g}} = \text{4.116 mol}\\\\\text{Moles of H$_{2}$O} = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{32.00 g}} = \text{2.191 mol}

Step 2. Identify the limiting reactant  

Calculate the moles of H₂O we can obtain from each reactant.

From NH₃:

The molar ratio of H₂O:NH₃ is 6:4.

\text{Moles of H$_{2}$O} = \text{4.116 mol NH$_{3}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{4 mol NH$_{3}$}} = \text{6.174 mol H$_{2}$O}

From O₂:  

The molar ratio of H₂O:O₂ is 6:5.  

\text{Moles of H$_{2}$O} = \text{2.191 mol O$_{2}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{5 mol O$_{2}$}} = \text{2.629 mol H$_{2}$O}

O₂ is the limiting reactant because it gives the smaller amount of H₂O.  

Step 3. Calculate the theoretical yield.

\text{Theor. yield } = \text{2.629 mol H$_{2}$O}\times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{47.4 g H$_{2}$O}\\\\\text{The maximum yield of H$_{2}$O is }\boxed{\textbf{47.4 g}}

6 0
2 years ago
Question 4
elixir [45]

Answer:

True

Explanation:

4 0
3 years ago
How much time would it take for 12000 atoms of nitrogen-13 (half-life is 7.13 s) to decay to 750 atoms?
Rainbow [258]
<h3>Answer:</h3>

28.52 seconds

<h3>Explanation:</h3>

Initial number of atoms of Nitrogen 12,000 atoms

Half-life = 7.13

Number of atoms after decay = 750 atoms

We are required to determine the time taken for the decay.

Note that half life is the time taken for a radioactive isotope to decay to a half of its original amount.

Using the formula;

Remaining amount = Initial amount × (1/2)^n , where n is the number of half lives

In our case;

750 atoms = 12,000 atoms × (1/2)^n

0.0625 = 0.5^n

n = log 0.0625 ÷ log 0.5

n = 4

But, 1 half life =7.13 seconds

Therefore;

Time taken = 7.13 seconds × 4

                  = 28.52 seconds

Therefore, the time taken for 12,000 atoms of nitrogen to decay to 750 atoms is 28.52 seconds

8 0
3 years ago
27.2g CuCl2 was dissolved in 2.50 L of the water. What is the molality of the solution?
stealth61 [152]

5.167g of calcium chloride is dissolved in 101.0mL of water in a calorimeter whose calorimeter constant is 15.3J/°C. The temperature rises from 18.4°C to 27.2 ...

5 0
2 years ago
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