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igomit [66]
3 years ago
7

If two kids kick the ball at the same time what is the motion on the ball will do?​

Chemistry
1 answer:
Artyom0805 [142]3 years ago
7 0

Explanation:

I think your correct it's A!!

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CuSO4.5H2O(k) ısı CuSO4(k) + 5 H2O(g) eşitliğine göre bakır sülfatın kristal suyu miktarı ve kaba formülü hesaplanacaktır.
baherus [9]

Answer:

159.609 g/mol

Explanation:

According to the CuSO4.5H2O (k) heat CuSO4 (k) + 5 H2O (g) equation, the crystal water amount of copper sulfate and its rough formula will be calculated.

Weight of copper sulfate containing crystal water = m1 = 249.62… g

Weight of copper sulfate without crystal water weighed = m2 = 159.62 g

Accordingly, calculate the x and y values ​​in the molecular formula of copper sulfate (xCuSO4.yH2O).

3 0
2 years ago
Saltpeter is a compound made of potassium (k), nitrogen (n), and oxygen (o). every 100.00 g of saltpeter contains 38.67 g potass
xeze [42]
First, we need to compute the mass of oxygen found in 100 grams of saltpeter:
mass of oxygen = 100 - (mass of potassium + mass of nitrogen)
                          = 100 - (38.67 + 13.86)
                          = 100 - 52.53
mass of oxygen in 100 grams saltpeter = 47.47 grams

Now, we can use cross multiplication to find the mass of oxygen in 328 grams saltpeter as follows:
mass of oxygen = (328 x 47.47) / 100 = 155.7016 grams
5 0
2 years ago
Read 2 more answers
Suppose you had a mixture of 1 moles of methanol and 1 mole of ethanol at a particular temperature. The vapor pressure of pure m
Natasha_Volkova [10]
The total pressure is given by:
P = ∑xiPi
P = 1/2 x 81 + 1/2 x 45
P = 63 kPa
5 0
3 years ago
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask?
horsena [70]
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask<span>The given are: </span>
<span><span>1.      </span>Mass = ?</span><span><span /></span>
<span><span>2.      </span>Density = 1298 g/L</span>
3.      Volume = 125mL to L
a. 125 ml x 0.001l/1ml = 0.125 L

<span>Formula and derivation: </span><span><span>
1.      </span>density = mass / volume</span> <span><span>
2.      mass </span>= density / volume</span>

<span>Solution for the problem: </span><span><span>

1. mass = </span></span> <span> 1298 g/L / 0.125 L = 10384g
</span>


8 0
3 years ago
Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemica
FinnZ [79.3K]

<u>Answer:</u> The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

0.130M=\frac{\text{Moles of NaI}}{0.400L}\\\\\text{Moles of NaI}=(0.130mol/L\times 0.400L)=0.52mol

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = \frac{1}{2}\times 0.52=0.26mol of lead (II) iodide

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

0.26mol=\frac{\text{Mass of lead (II) iodide}}{461.1g/mol}\\\\\text{Mass of lead (II) iodide}=(0.26mol\times 461.1g/mol)=119.89g

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

4 0
3 years ago
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