linear charge density of system of two line charges is given as

now as we know that electric field due to a line charge at some distance from it is given by

so here we will first find the electric field of first line charge at the position of other line charge


now as we know that

here q = charge on the line charge system at which force is required
E = electric field on that system of charge where force is required
now we can find the charge by


Now using the above formula



so force on the part of wire is F = 0.0811 N
Answer:a)1.11×10^-21Nm
b) 1.16×10^-3m
Explanation:see attachment
Answer:
Explanation:
Energy stored in a capacitor
= 1/2 C₁V²
capacity of a capacitor
c = εK A / d
k is dielectric and d is distance between plates .
When the distance between the plates is halved and then filled with a dielectric (κ = 4.3)
capacity becomes 4.3 x 2 times
New capacity
C₂ = 8.6 C₁
Energy of modified capacitor
1/2 C₂ V²= 1/2 x 8.6 c x V²
Energy becomes
8.6 times.
Energy stored = 8.6 x 10⁻⁴ J
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In short, Your Answer would be: "False"
Hope this helps!