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Sveta_85 [38]
3 years ago
15

I want to take a picture of the question and get the answer

Physics
1 answer:
OleMash [197]3 years ago
5 0
When you take a picture it pulls up people who asked the same question and they’ll have a answer you can use
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The SI system uses three base units. Is this true or false?
ozzi
The\text{ SI }system\text{ uses seven }base\text{ units, hence the statement is false}

8 0
1 year ago
Read 2 more answers
If a liquid has a density of 1.67 g/cm^3, what is the volume of 45g of the liquid?
Aloiza [94]

Answer:

V = 26.95 cm³

Explanation:

Density is given by the formula :

ρ = m÷V

Density = mass ÷ Volume

Given both density and mass we rearrange, substitute and solve for Volume :

Rearranging the equation to make Volume the subject :

ρ = m÷V

ρV = m

V = m÷ ρ

Now substitute :

V = 45 ÷ 1.67

V = 26.9461077844

Take 2 decimal places as the density is 2 decimal places :

V = 26.95

Units will be cm³ as it is volume

Hope this helped and have a good day

8 0
2 years ago
Explain the differences between horticulture and agriculture.
sammy [17]
<h2><u>Hello </u><u>There</u></h2>

\tt{Difference \:  Between \:   \underline\red {Horticulture} \:  And \:   \underline\green{Agriculture}}

\text{\underline\red {Horticulture}}

The Cultivation of Fruits, Vegetables and Flowers for domestic and international markets are called Horticulture.

\text{\underline\green{Agriculture}}

It is science, art and occupation of cultivating the soil, producing crops and livestock. It is systematic and controlled use of living organisms and the environment to improve the human condition.

<h3>Hope This Helps</h3>
6 0
2 years ago
Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri
Ainat [17]

Answer:

The taken is  t_A  = 19.0 \ s

Explanation:

Frm the question we are told that

  The speed of car A is  v_A  =  22 \ m/s

   The speed of car B is  v_B  = 29.0 \ m/s

     The distance of car B  from A is  d = 300 \ m

     The acceleration of car A is  a_A  = 2.40 \ m/s^2

For A to overtake B

    The distance traveled by car B  =  The distance traveled by car A - 300m

Now the this distance traveled by car B before it is overtaken by A is  

          d = v_B * t_A

Where t_B is the time taken by car B

Now this can also be represented as using equation of motion as

      d = v_A t_A  + \frac{1}{2}a_A t_A^2 - 300

Now substituting values

       d = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

Equating the both d

       v_B * t_A = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

substituting values

   29 * t_A = 22t_A  + \frac{1}{2} (2.40)^2 t_A^2 - 300

   7 t_A = \frac{1}{2} (2.40)^2 t_A^2 - 300

  7 t_A =1.2 t_A^2 - 300

   1.2 t_A^2 - 7 t_A - 300  = 0

Solving this using quadratic formula we have that

     t_A  = 19.0 \ s

7 0
3 years ago
If a cat can exert 2000N Of Force to move a trailer 50m is 20 seconds how much power did the car use ?
inessss [21]

им putins брат, почему вы обманываете нашу систему образования, Это теперь запрещено в России.

8 0
2 years ago
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