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ololo11 [35]
3 years ago
7

Explain why serine proteases do not catalyze hydrolysis if the amino acid at the hydrolysis site is a D-amino acid. Trypsin, for

example, cleaves on the C-side of L-Arg and L-Lys, but not on the C-side of D-Arg and D-Lys. Explain why serine proteases do not catalyze hydrolysis if the amino acid at the hydrolysis site is a D-amino acid. Trypsin, for example, cleaves on the -side of L- and L-, but not on the -side of D- and D-. All the naturally occurring amino acids are D-amino acids, while active centres of serine proteases are nearly all L. All the naturally occurring amino acids are L-amino acids, while active centres of serine proteases are nearly all D. The side chains of D-Arg and D-Lys are not positioned to bind correctly at the active site. None of the above.
Chemistry
1 answer:
tatiyna3 years ago
5 0

Answer:

D. The side chains of D-Arg and D-Lys are not positioned to bind correctly at the active site

Explanation:

Stereospecificity is the ability to distinguish between stereoisomers of of a particular compound. L- and D- structures of compounds in living organisms are usually present in only one form due to stereospecificity. For example, naturally occuring amino acids in proteins are usually present as L-isomers.

Since enzyme are proteins, their active sites are composed of L-amino acid and they show stereospecificity in the reactions they catalyze. In their binding sites, only substrates complementary in structure can bind in order for catalysis to proceed. Therefore, only amino acids in the L- configuration are complementary to the active site of enzymes.

In the case of serine proteases, The side chains of -Arg and D-Lys will not be positioned properly for binding at the binding site of serine proteases, therefore, no catalysis will occur. On the other hand, L-Arg and L-Lys can bind to the catalytic site of serine proteases since they are complementary fits to the active site of the enzymes.

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How many moles of dinitrogen tetroxide (N2O4) are in 6.49 x 109 particles?
yan [13]

Answer: There are 1.08 \times 10^{-14} moles N_{2}O_{4} present in 6.49 \times 10^9 particles.

Explanation:

According to the mole concept, 1 mole of a substance contains 6.022 \times 10^{23} particles.

Hence, number of moles present in 6.49 \times 10^9 particles are calculated as follows.

No. of moles = \frac{6.49 \times 10^9}{6.022 \times 10^{23}} mol

                      = 1.08 \times 10^{-14} mol

Thus, there are 1.08 \times 10^{-14} moles N_{2}O_{4} present in 6.49 \times 10^9 particles.

6 0
3 years ago
Read 2 more answers
Which of the following is not an amphoteric substance?
snow_lady [41]

Sắt oxit

Explanation:

7 0
3 years ago
A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percentage, the student measures out 5.84 grams o
julsineya [31]

Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

3 0
4 years ago
In at least 4 complete sentences, describe the similarities and differences between Avogadro's Law and Charles' Law.
viktelen [127]

answer

Avogadro's law states that, at constant temperature and pressure, the volume of a gas is directly proportional to the number of moles present. In other words, equal volumes of gases at the same pressure and temperature contain the same number of molecules - this is true regardless of their physical properties or chemical nature.

This number of molecules is

6.022

⋅

10

23

and is known as Avogadro's number,

N

A

.

Matematically, Avogadro's law can be written like this

V

n

=

c

o

n

s

t

, or, better yet,

V

1

n

1

=

V

2

n

2

.

Avogadro's law, as well as Boyle's law and Charles' law, are special cases of the ideal gas law,

P

V

=

n

R

T

. If temperature and pressure are kept constant, and knowing that

R

is of course constant, then

P

V

=

n

R

T

→

P

V

n

=

R

T

→

V

n

=

R

T

P

=

c

o

n

s

t

, which represents Avogadro's law.

The ideal gas law can also be written to incorporate

N

A

, since the number of moles are actually the number of molecules divided by Avogadro's number

P

V

=

N

N

A

⋅

R

T

, where

N

represents the number of molecules.

7 0
3 years ago
a solution of KCl in water has a concentration of 0.243 M. The solution has a volume of 0.580 L. How many grams of KCl are prese
Novosadov [1.4K]

Answer:

10.5 g

Explanation:

Step 1: Given data

  • Molar concentration of the solution (C): 0.243 M
  • Volume of solution (V): 0.580 L

Step 2: Calculate the moles of solute (n)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

n = M × V

n = 0.243 mol/L × 0.580 L = 0.141 mol

Step 3: Calculate the mass corresponding to 0.141 moles of KCl

The molar mass of KCl is 74.55 g/mol.

0.141 mol × 74.55 g/mol = 10.5 g

8 0
3 years ago
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