The law of conservation of energy states that if the system gains heat the surroundings _______

Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:

12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: $n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}$

∴ mass of S in 2 moles of S: $w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g$

Given reaction: 2S + 3O₂ → 2 SO₃

In this reaction, the limiting reagent is S

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ The amount of heat produced by 42.8 g S:

$x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ$

$\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J$

$(\because 1 kJ = 10^{3} J)$

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

8 0

3 years ago

List four energy resources

Nuetrik [128]

Answer:

Nuclear

Solar

Wind

Hydro

Geo-Thermal

6 0

3 years ago

Read 2 more answers

Help will give brainliest!!

GarryVolchara [31]

Half reaction :

Oxidation

Cu ⇒ Cu²⁺ + 2e⁻

Reduction

2Ag⁺+ 2e⁻ ⇒2Ag

<h3>Further explanation</h3>

Given

Reaction

Cu+2AgNO₃⇒Cu(NO₃)₂+2Ag

Required

Oxidation and reduction half-reactions

Solution

Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.

Oxidation

Cu ⇒ Cu²⁺ + 2e⁻

0 to +2

Reduction

2Ag⁺+ 2e⁻ ⇒2Ag

+1 to 0

6 0

3 years ago

Number of Electrons = Number of Protons = Atomic __________________

Stella [2.4K]

Number

The atomic number is the number of protons in one atom of an element.

Hope this helps!

3 0

3 years ago

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NEED HELP ASAP!!!!! PLEASE HELP!!!!! NEED HELP ASAP!!!!!

r-ruslan [8.4K]

Answer:

CH4 - Methane

B2Si - Diboron monosilicide

N2O5 - Dinitrogen pentoxide

CO2 - Carbon dioxide

Explanation:

When it comes to naming covalent compounds, there are several rules.

The name is derived based on the formula. For example, N2O5. The first element is nitrogen. To the name of the element, you add the prefix that tells us how many of its atoms are in the compound. In this case, there are two atoms, which means that the prefix will be di- (dinitrogen). The second element is oxygen. You are supposed to take only the root of the second element's name and then add the prefix denoting the number of its atoms and the suffix -ide (pentoxide). This is how we'll get dinitrogen pentoxide.

The only exception is methane (CH4), which is an organic compound. Organic compounds are named using the IUPAC nomenclature.

3 0

3 years ago

The law of conservation of energy states that if the system gains heat the surroundings ________?