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ololo11 [35]
3 years ago
9

If chemical reactions involve atoms disconnecting from each other and then connecting with different atoms in different ways, wh

y do you think energy would go into or out of chemical reactions? In other words, how could energy be involved in disconnecting or connecting atoms to each other?
Chemistry
1 answer:
Valentin [98]3 years ago
5 0

Answer:  Energy can  be involved in disconnecting or connecting atoms to each other as the energy is used to break the bonds between the atoms ,so the reaction could proceed.

Explanation:<u> The statement can be well explained by the  Planck's quantum theory , which states -:</u>

  • In the form of small energy packets known as quanta of energy, energy is not released continuously, but discontinuously.
  • The energy of each quantum is directly proportional to radiation frequency, i.e. E is directly proportional to v, where v is frequency E = hv, where h is the proportionality constant known as the constant of Planck.
  • Any integer quanta will be the total energy of the radiation emitted or absorbed. Let the 'E' be the total radiation energy. So, when n is an integer, E'=nhv.

Hence, the given answer is based on the Planck's Quantum theory.

You might be interested in
Neutral atom contains 22 protons and 24 neutrons​
dezoksy [38]

Answer:

And contains 22 electrons

5 0
3 years ago
calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

P_w=0 bar+(-3.406 ) bar

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
3 years ago
An analytical chemist is titrating 118.3 mL of a 0.3500 M solution of butanoic acid (HC3H7CO2) with a 0.400 M solution of KOH. T
TEA [102]

Answer:

pH = 12.33

Explanation:

Lets call HA = butanoic acid and A⁻ butanoic acid and its conjugate base butanoate respectively.

The titration reaction is

HA + KOH ---------------------------- A⁻ + H₂O + K⁺

number of moles of HA :   118.3 ml/1000ml/L x 0.3500 mol/L = 0.041 mol HA

number of  moles of OH  : 115.4 mL/1000ml/L x 0.400 mol/L  = 0.046 mol A⁻

therefore the weak acid will be completely consumed and what we have is  the unreacted strong base KOH which will drive the pH of the solution since the contribution of the conjugate base is negligible.

n unreacted KOH = 0.046 - 0.041 = 0.005 mol KOH

pOH = - log (KOH)

M KOH = 0.005 mol / (0.118.3 +0.1154)L = 0.0021 M

pOH = - log (0.0021) = 1.66

pH = 14 - 1.96 = 12.33

Note: It is a mistake to ask for the pH of the <u>acid solutio</u>n since as the above calculation shows we have a basic solution the moment all the acid has been consumed.

4 0
3 years ago
Which of the following represents the atomic number of an element?
Anna11 [10]

Answer:

The atomic number is the number of protons in the nucleus

4 0
3 years ago
Jamie rolls a 6-sided die 30 times and determines that the experimental probability of rolling a 2 is Start Fraction 1 over 15 E
anyanavicka [17]

Answer:

Conduct more trials

Explanation:

Theoretical Probability can be defined as what someone is expecting to happen

Experimental Probability on the other hand, is defined as what actually happens.

Probability is usually calculated in the same way for experimental probability and that of theoretical probability. You divide the total number of possible ways in which a particular outcome can happen, by the total number of outcomes itself.

In Experimental probability, the more times a probability is tried, it gets closer and even more closer to theoretical probability.

So, for the question, Jamie should improve the number of tries more, so as to get his experimental probability results to be closer to the theoretical probability result.

8 0
3 years ago
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