(a) 5.66 m/s
The flow rate of the water in the pipe is given by
![Q=Av](https://tex.z-dn.net/?f=Q%3DAv)
where
Q is the flow rate
A is the cross-sectional area of the pipe
v is the speed of the water
Here we have
![Q=1.20 m^3/s](https://tex.z-dn.net/?f=Q%3D1.20%20m%5E3%2Fs)
the radius of the pipe is
r = 0.260 m
So the cross-sectional area is
![A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%20%3D%20%5Cpi%20%280.260%20m%29%5E2%3D0.212%20m%5E2)
So we can re-arrange the equation to find the speed of the water:
![v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7BQ%7D%7BA%7D%3D%5Cfrac%7B1.20%20m%5E3%2Fs%7D%7B0.212%20m%5E2%7D%3D5.66%20m%2Fs)
(b) 0.326 m
The flow rate along the pipe is conserved, so we can write:
![Q_1 = Q_2\\A_1 v_1 = A_2 v_2](https://tex.z-dn.net/?f=Q_1%20%3D%20Q_2%5C%5CA_1%20v_1%20%3D%20A_2%20v_2)
where we have
![A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s](https://tex.z-dn.net/?f=A_1%20%3D%200.212%20m%5E2%5C%5Cv_1%20%3D%205.66%20m%2Fs%5C%5Cv_2%20%3D%203.60%20m%2Fs)
and where
is the cross-sectional area of the pipe at the second point.
Solving for A2,
![A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7BA_1%20v_1%7D%7Bv_2%7D%3D%5Cfrac%7B%280.212%20m%5E2%29%285.66%20m%2Fs%29%7D%7B3.60%20m%2Fs%7D%3D0.333%20m%5E2)
And finally we can find the radius of the pipe at that point:
![A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cpi%20r_2%5E2%5C%5Cr_2%20%3D%20%5Csqrt%7B%5Cfrac%7BA_2%7D%7B%5Cpi%7D%7D%3D%5Csqrt%7B%5Cfrac%7B0.333%20m%5E2%7D%7B%5Cpi%7D%7D%3D0.326%20m)
False because your deltoids are in your shoulders not your back
Answer:
A. The project's energy costs will decrease
Explanation:
Since the project is located in an area with a demand-response program and on a site that has enough room for a wind-turbine to allow for on-site renewable energy.
Hence, the project's energy costs will decrease very well because it's implementing both of these strategies;
- Area with demand-response program.
- On-site renewable energy.
A calorimeter measures the amount of heat in a chemical reaction. So the answer would be C, specific heat.
Answer:
- The emf of the generator is 6V
- The internal resistance of the generator is 1 Ω
Explanation:
Given;
terminal voltage, V = 5.7 V, when the current, I = 0.3 A
terminal voltage, V = 5.1 V, when the current, I = 0.9 A
The emf of the generator is calculated as;
E = V + Ir
where;
E is the emf of the generator
r is the internal resistance
First case:
E = 5.7 + 0.3r -------- (1)
Second case:
E = 5.1 + 0.9r -------- (2)
Since the emf E, is constant in both equations, we will have the following;
5.1 + 0.9r = 5.7 + 0.3r
collect similar terms together;
0.9r - 0.3r = 5.7 - 5.1
0.6r = 0.6
r = 0.6/0.6
r = 1 Ω
Now, determine the emf of the generator;
E = V + Ir
E = 5.1 + 0.9x1
E = 5.1 + 0.9
E = 6 V