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Debora [2.8K]
3 years ago
5

Animals can change the energy in food into energy the animals can use. What type of energy is in the food before the animals cha

nge it? A. chemical energy B. energy of motion C. heat energy D. light energy
Chemistry
1 answer:
SVEN [57.7K]3 years ago
7 0

D. Light energy is the right answer

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Which of the following is the correct formula for copper (I) sulfate trihydrate? CuSO4 · 3H2O
PilotLPTM [1.2K]
It is either the 3rd answer or the 4th answer. Both are correct ways to write hydrates, but I was taught the 4th way. Just make sure this answer matches the format of the examples your teacher gave you.
6 0
3 years ago
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How far in advance is weather forecasting most accurate
Vesnalui [34]

I'm like 99% sure its one week

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3 years ago
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A 0.500-g sample containing Na2CO3 plus inert matter is analyzed by adding 50.0 mL of 0.100 M HCl, a slight excess, boiling to r
Yakvenalex [24]

The percentage by mass of Na2CO3 in the sample is 48%.

The equation of the reaction of Na2CO3 with HCl;

Na2CO3(aq) + 2HCl(aq) ------> 2NaCl(aq) + H2O(l) + CO2(g)

Since the HCl is in excess, the excess is back titrated with NaOH as follows;

NaOH (aq) + HCl(aq) ---->NaCl(aq) + H2O(l)

Number of moles of HCl added =  0.100 M × 50/1000 L = 0.005 moles

Number of moles of NaOH added = 5.6/1000 ×  0.100 M = 0.00056 moles

Since the reaction of NaOH and NaOH is 1:1, 0.00056 moles of HCl reacted with excess HCl.

Amount of HCl that reacted with Na2CO3 =  0.005 moles -  0.00056 moles = 0.0044 moles

Now;

1 mole of Na2CO3 reacts with 2 moles of HCl

x moles of Na2CO3 reacts with 0.0044 moles of HCl

x = 1 mole × 0.0044 moles / 2 moles

x = 0.0022 moles

Mass of Na2CO3 reacted = 0.0022 moles × 106 g/mol = 0.24 g

Percentage of Na2CO3  in the sample = 0.24 g/ 0.500-g × 100/1 = 48%

Learn more about back titration: brainly.com/question/25485091

5 0
2 years ago
What is the total number of protons in an h2o atom?
NISA [10]
The atomic number of H2O is 18 hence it contains 18 protons. Hope this helps.
5 0
3 years ago
The highest pressure ever produced in a laboratory setting was about 2.0 x 10 6 atm. If we have a
tigry1 [53]

Answer:

Volume = 72.7272

Explanation:

if only pressure and volume change, then we can do some simple math to find the answer.

2 x 10 ^ 6 times 1 x 10 ^-5 = 20

pressure and volume must equal 20

20 = 0.275 x volume

20 / 0.275 = new volume

I don't remember significant digits but your volume is 72.72727272 just repeated

8 0
3 years ago
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