Answer:
22.715 moles of oxygen are used
Explanation:
Given data:
Number of moles of ethane = 6.49 mol
Number of moles of O₂ required = ?
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Now we will compare the moles of oxygen with ethane.
C₂H₆ : O₂
2 : 7
6.49 : 7/2×6.49 = 22.715 mol
Thus, 22.715 moles of oxygen are used.
Answer:
The properties <u>that </u><u>do not vary</u><u> with the variation in the quantity of the material are called as </u><u>intensive property</u>.
While the <u>extensive properties</u><u> are those which </u><u>vary with the variation in the quantity of the material</u>.
Intensive properties:
Mass and volume
Extensive properties:
Density and melting point
Explanation:
The properties <u>that </u><u>do not vary</u><u> with the variation in the quantity of the material are called as </u><u>intensive property</u>.
While the <u>extensive properties</u><u> are those which </u><u>vary with the variation in the quantity of the material</u>.
Intensive properties:
Mass and volume, as with increase in quantity of the material mass and volume increases.
Extensive properties:
Density and melting point, as they remain constant for a object or material
The chemical composition of water is H2O – two hydrogen atoms and one oxygen atom. Water has special properties because of the way these atoms bond together to form a water molecule, and the way the molecules interact with each other. ... Water's polarity allows it to dissolve other polar substances very easily.
Chemical compounds<span> tend to </span>dissolve more quickly in hot solvent than in cold solvent, t<span>he </span>solvent<span> molecules have </span>more<span> energy to pull the solute particles apart. Give an example of two liquids that are miscible.
https://www.studyblue.com/notes/note/n/chemistry/deck/938054
</span>
<span>1.43g x (1 mole / 233g) x (6.022x10^23 particles / mole) = 3.70 x 10^ 21 particles</span>
