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4 years ago

A 200 N force is applied to a 50.0 kg object moving at 3.0 m/s. How fast will it be going at 4.0 s?

Physics

1 answer:

blsea [12.9K]4 years ago

8 0

Answer:

19.0 m/s

Explanation:

First of all, we can find the acceleration of the object by using Newton's second law:

$F=ma$

where

F = 200 N is the net force applied to the object

m = 50.0 kg is the mass of the object

a is the acceleration

Solving for a,

$a=\frac{F}{m}=\frac{200 N}{50.0 kg}=4.0 m/s^2$

Now we can find the final speed of the object:

$v=u+at$

where

u = 3.0 m/s is the initial speed

a = 4.0 m/s^2 is the acceleration

t = 4.0 s is the time

Substituting,

$v=3.0 m/s + (4.0 m/s^2)(4.0 s)=19.0 m/s$

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Answer:

The frog takes 8 jumps to reach top of well

Explanation:

Given data

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Total number of leaps the frog needed to escape from well

Solution

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Similarly after 7 jumps

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=14+3

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3 years ago

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Answer:

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