<span>320. seconds
The ideal gas law is
PV = nRT
where
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = the ideal gas constant
T = absolute temperature of the gas.
Since we're going to want the volume, solve for V
PV = nRT
V = nRT/P
755 mmHg converts to 100658.11 Pascals
25 C = 298.15 K
Let's calculate nT/P, then we'll multiply by R
1 mol * 298.15 K / 100658.11 Pa = 0.002962007 K mol/Pa
The value for R in the most convenient units is 8.3144598 m^3 Pa/(K mol), so
0.002962007 K mol/Pa * 8.3144598 m^3 Pa/(K mol) = 0.024627486 m^3
So 1 mole of air at the specified temperature and pressure has a volume of 24.627 liters. The rest of the problem is now trivial. Just divide by the rate of consumption, so
24.627 l / 0.0770 l/s = 319.8374798 s
Rounding the result to 3 significant figures gives 320. seconds.</span>
They all end with suffix "-ide"
In short, Your Answer would be Option C
Hope this helps!
Answer:
Displacement by cyclist is zero.
Explanation:
In the given question bicyclist is travelling in a rectangular track having P , Q and R edges.
The bicyclist starts from P and travel through Q and R and returned to P again.
We need to find its displacement.
We know displacement of a body is its difference between its initial position to final position.
Here in the given question the bicyclist returns to P again.
Therefore, total displacement by bicyclist is zero.
Hence, this is the required solution.
Answer:
Zero
Explanation:
As we know that the force and the motion direction should always be perpendicular to each other due to which the work is done by static friction be zero
Therefore
F.dcos(theta) = F.d cos(90) = 0
Hence, the work done by static friction is zero
Therefore the same is to be considered
