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uranmaximum [27]
3 years ago
10

the moon revolves around the earth in a nearly circular orbit kept by gravitational force exerted by the earth work done will be

Physics
1 answer:
rodikova [14]3 years ago
3 0

Answer:

Zero because the applied force is perpendicular to the motion of the object.

No work is done on an object moving is a circular path about a central attractive force.

Any work done in such a case would result in a change in the orbit.

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A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a
aliya0001 [1]

Answer:

P_2 = -1.9 \times 10^8 Pa

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

Q = A_1v_1 = A_2v_2

at the upper end the area is given as

A_1 = \pi r_1^2

A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2

Also at the other end

A_2 = \pi r_2^2

A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2

now the speed at two ends is given as

v_1 = \frac{20}{1.26 \times 10^{-3}}

v_1 = 159.15 m/s

v_2 = \frac{20}{0.314 \times 10^{-3}}

v_2 = 637 m/s

now by Bernoulli's theorem we have

P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2

now we have

0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0

Now we have

P_2 = -1.9 \times 10^8 Pa

4 0
3 years ago
Which phrase describes an atom?
kiruha [24]

You haven't included the list of choices that goes with the question, so it's
impossible for me to choose the correct one, or to help you choose it.

Regarding my ability to answer the question and collect the 5-point bounty,
I'm free to make up any phrase of my own that correctly describes an atom.

-- very very very very very very very tiny

-- includes even tinier particles, with electric charges
   both positive and negative

-- smaller than the wavelength of visible light

4 0
3 years ago
What is the current flowing through the circuit shown? (V= 120 V, R₁ = 20 02,
spayn [35]

Assumed that resistors are connected in series .

  • R_net=20+50+10=80ohm

  • Voltage=V=120V

Current=I

  • V/R
  • 120/80
  • 3/2
  • 1.5A
3 0
2 years ago
A hydrogen bond forms by the electrostatic interaction of opposite charges in two molecules. If
Darya [45]

The force between the molecules involved in the bond is 6. 426 *10^-11 Newton

<h3>How to determine the force</h3>

Using the formula:

F = K[q1 x q2]/D^2

where K is coulombs constant =9 *10 ^9 Nm^2/C^2.

q1  and q2 = charges  =  1.60x10 -20C

d = distance between the charges = 2x10 -10 m

Substitute the values into the formula

F =  9 * 10^9\frac{ 1.60*10^ -20 *  1.60 *10^ -20}{2x10^ -10^{2} }

F = 9 *10^9\frac{2. 856* 10^-40}{4* 10^-20}

F = 9* 10^9 * 7. 14* 10^-21

F = 6. 426 * 10^-11 Newton

Thus, the force between the molecules involved in the bond is 6. 426 *10^-11 Newton

Learn more about electrostatic force here:

brainly.com/question/8424563

#SPJ1

5 0
2 years ago
A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 22 ft/s2. What is the dist
makvit [3.9K]

Answer:

The correct solution is "122.2211".

Explanation:

Given:

deceleration,

a = 22 ft/sec²

Initial velocity,

V_i=50 \ m/h

Now,

V_i=50 \ m/h\times 5280 \ ft/m\times hr/3600 \ s

    =73.333 \ ft/sec

Now,

Final velocity,

V_f=0

Initial velocity,

V_{initial} = 73.333 \ ft/sec

hence,

⇒ V_f^2=V_i^2+2aD

By putting the values, we get

      0=(73.333)^2+2\times( -22) D

  44D=(73.333)^2

      D=\frac{(73.333)^2}{44}

          =122.2211

3 0
4 years ago
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