Answer:
A. 240 J
B. 60 J
C. 90 J
D. 0 J
E. 50 J
Explanation:
A. Determination of the potential energy of the coconut while it is still in the tree
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 12 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 12
PE = 240 J
B. Determination of the potential energy of the coconut when it hits the bystander on the head,
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 3 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 3
PE = 60 J
C. Determination of the potential energy of the coconut when it bounces up to its maximum height,
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 3 + 1.5 = 4.5 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 4.5
PE = 90 J
D. Determination of the potential energy of the coconut when it lands on the ground,
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 0 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 0
PE = 0 J
E. Determination of the potential energy of the coconut when it rolls into a ground hole, and falls 2.50 m to the bottom of the hole.
Mass (m) = 2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) = 2.50 m
Potential energy (PE) =.?
PE = mgh
PE = 2 × 10 × 2.50
PE = 50 J
