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2 years ago

Are some chemicals safe while others are dangerous?

Chemistry

1 answer:

avanturin [10]2 years ago

4 0

Answer:

yes

Explanation:

some chemicals can kill you with just one drop.

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A compound distributes between benzene (solvent 1) and water (solvent 2) with a distribution coefficient, K = 2.7. If 1.0g of th

mote1985 [20]

Explanation:

The given data is as follows.

Solvent 1 = benzene, Solvent 2 = water

$K_{p}$ = 2.7, $V_{S_{2}}$ = 100 mL

$V_{S_{1}}$ = 10 mL, weight of compound = 1 g

Extract = 3

Therefore, calculate the fraction remaining as follows.

$f_{n} = [1 + K_{p}(\frac{V_{S_{2}}}{V_{S_{1}}})]^{-n}$

= $[1 + 2.7(\frac{100}{10})]^{-3}$

= $(28)^{-3}$

= $4.55 \times 10^{-5}$

Hence, weight of compound to be extracted = weight of compound - fraction remaining

= 1 - $4.55 \times 10^{-5}$

= 0.00001

or, = $1 \times 10^{-5}$

Thus, we can conclude that weight of compound that could be extracted is $1 \times 10^{-5}$ .

7 0

2 years ago

Read 2 more answers

A chemist titrates 160.0mL of a 0.3403M aniline C6H5NH2 solution with 0.0501M HNO3 solution at 25°C . Calculate the pH at equiva

maxonik [38]

Answer : The pH of the solution is, 5.24

Explanation :

First we have to calculate the volume of $HNO_3$

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of $C_6H_5NH_2$ .

$M_2\text{ and }V_2$ are the final molarity and volume of $HNO_3$ .

We are given:

$M_1=0.3403M\\V_1=160.0mL\\M_2=0.0501M\\V_2=?$

Putting values in above equation, we get:

$0.3403M\times 160.0mL=0.0501M\times V_2\\\\V_2=1086.79mL$

Now we have to calculate the total volume of solution.

Total volume of solution = Volume of $C_6H_5NH_2$ + Volume of $HNO_3$

Total volume of solution = 160.0 mL + 1086.79 mL

Total volume of solution = 1246.79 mL

Now we have to calculate the Concentration of salt.

$\text{Concentration of salt}=\frac{0.3403M}{1246.79mL}\times 160.0mL=0.0437M$

Now we have to calculate the pH of the solution.

At equivalence point,

$pOH=\frac{1}{2}[pK_w+pK_b+\log C]$

$pOH=\frac{1}{2}[14+4.87+\log (0.0437)]$

$pOH=8.76$

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-8.76\\\\pH=5.24$

Thus, the pH of the solution is, 5.24

4 0

3 years ago

100 POINTS ANSWER HURRY

prisoha [69]

C. Not all mixtures have solutes and solvents

7 0

3 years ago

Read 2 more answers

In the following reaction, how many moles of CO2 will form if 10 moles of C3H4 are reacted? How many moles of O2 will also be co

umka2103 [35]

Answer:

40 moles of O₂

30 moles of CO₂

Explanation:

Given parameters:

Number of moles of C₃H₄ = 10moles

Unknown:

Number of moles of CO₂ = ?

Solution:

The number of moles helps to understand and make quantitative measurements involving chemical reactions.

We start by solving this sort of problem by ensuring that the given equation is properly balanced;

C₃H₄ + 4O₂ → 3CO₂ + 2H₂O

We can clearly see that all the atoms are conserved.

Now, we work from the known to unknown. We know the number of moles of C₃H₄ to be 10moles;

1 mole of C₃H₄ reacted with 4 moles of O₂

10 moles of C₃H₄ will react with 10 x 4 = 40moles of O₂

1 mole of C₃H₄ will produce 3 moles of CO₂

10 moles of C₃H₄ will produce 10 x 3 = 30moles of CO₂

4 0

2 years ago

What does vinegar do to eggs

andre [41]

Eggshells are made primarily of calcium carbonate. The acid in vinegar softens the calcium of the eggshell. Adding a little vinegar to the water when boiling eggs is an old cook’s trick that makes them easier to peel.

A link to this experiment is below in the comment box

7 0

2 years ago