The aggregation state, or state of aggregation, is the form of the substance in different kinds of states. For example, Bromine could occur as solid, liquid or gas. For all these forms, its molecular aggregation is diatomic in nature. It is always written as Br₂.
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
The charge of an e- is 1.60217657×10^-19 coulombs I.e. A very small number!
So 1 coulomb is much much bigger than the charge of an electron.
(x1,y1) (x2,y2)
(32,15) (212,135)
y = mx + b
m=(y2-y1)/(x2-x1)
m=.66667
y = .66667*(x) + b
Plug in #s to test for b value
15 = .66667*(32) + b
b = -6.334
y = mx + b
y = .6667*(x) + (-6.334)
F = .6667*(F) + (-6.334)
F = (.6667*(F) = -6.334
(F - .6667F) = -6.334
F(1 - .6667) = -6.334
F = -19
ThermX = F @ -19 degrees
Brainliest please!
No they can not be identified through a karyotype such as sickle cell anemia cant be detected through karyotyping because there will be n observal change.
Hope this helps
