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gayaneshka [121]
3 years ago
15

A cell supplies a current of 0.6A through a 2 Ohms coil and a current of 0.2A through a 7 Ohms coil. Calculate the e.M.F. Of the

cell.
Physics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

E.M.F = 1.5 V

Explanation:

The equation relating EMF, internal resistance and external resistance is given by;

E = Ir + IR

Where; E is the EMF, I is the current, r is the internal resistance, and R is the external resistance.

Therefore;

When I = 0.6 A and R = 2Ω

E = 0.6 r + (0.6 × 2)

E = 0.6r + 1.2

When I = 0.2 A and R = 7 Ω

E = 0.2 r + (0.2 × 7)

E = 0.2 r + 1.4

Solving simultaneously;

E = 0.6r + 1.2

E = 0.2 r + 1.4 ; eliminating E

0 = 0.4 r - 0.2

0.4 r = 0.2

     r = 0.5

Therefore;

E = 0.2(0.5) + 1.4

   = 0.1 + 1.4

   = 1.5 V

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Alex Ar [27]

Answer:

 y = 77.74 10⁻⁵ m

Explanation:

For this exercise we can use Newton's second law

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        a = F / m

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This is the vertical acceleration of the electron.

Now let's use kinematics to find the time it takes to move the

         x= 29 mm = 29 10⁻³ m

On the x axis

            v = x / t

            t = x / v

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            t = 17 10⁻¹⁰ s

Now we can look for vertical distance at this time.

            y = v_{oy} t + ½ a t²

            y = 0 + ½ 0.538 10¹⁵ (17 10⁻¹⁰)²

            y = 77.74 10⁻⁵ m

3 0
3 years ago
Read 2 more answers
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Margarita [4]

Answer:

Explanation:

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7 0
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likoan [24]

Answer:

Explanation:

1. when both sides of the reactants and the products are equal

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2. no they are put to balance the equation

3. nope they are treated equally as all the other states

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5. yup

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