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Kipish [7]
3 years ago
11

NEED HELP!!!!

Physics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

The correct choice is D. Concentric exercise can be hard on joints, so she should be very careful.

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When tightening a bolt, you push perpendicularly on a wrench with a force of 167 N at a distance of 0.1450 mm from the centre of
Vlad1618 [11]

Answer:0.0242 Nm

Explanation: The distance of 0.145 mm is very small. This will also result in a small ttorque. The question would make more sense if the distance was 0.145 m. Answering with the 0.145 mm as distance :

Changin from mm to m : 1mm=0.001m

0.145 mm = 0.000145 m

The formula for Torque is T=Fxd

Wher F is the force and d is the perpendicular distance between the centre of the bolt and the applied force.

T= 167 x 0.000145 = 0.024215 Nm

5 0
3 years ago
A plane has a speed of 285 km/h west relative to the air. A wind blows 25 km/h east relative to the ground. what are the planes
geniusboy [140]

Answer:

260 km/h

Explanation:

Motion is said to be relative when the motion observed by the observer depends on the location (frame) of the observer.

When two objects are moving in opposite directions, the relative motion is obtained by subtraction.

Hence  the plane is moving at (285 - 25) km/h giving 260 km/h

3 0
3 years ago
The velocity of a spinning gyroscope drops from 12 rad/s to 6 rad/s due to deceleration of -1.2 rad/s^2. how much time expires d
Rudik [331]
<span>5 seconds expired during the deceleration. Top rotated 45 radians during these 5 seconds. First, calculate the chance in velocity, by subtracting the initial velocity from the final velocity. So 6 rad/s - 12 rad/s = -6 rad/s So we lost a total of 6 rad/s. Divide that by the deceleration to give the number of seconds. So -6 rad/s / -1.2 rad/s^2 = 5 s So it takes 5 seconds for the deceleration to happen. The equation that expresses the number of radians performed under constant deceleration with an initial velocity is d = VT + 0.5 AT^2 where d = distance V = initial velocity T = time A = acceleration Substituting the known values gives. d = VT + 0.5 AT^2 d = 12 rad/s * 5s + 0.5 * -1.2 rad/s^2 (5s)^2 d = 60 rad -0.6 rad/s^2 *25s^2 d = 60 rad -15 rad d = 45 rad So the top rotated 45 radians while decelerating from 12 rad/s to 6 rad/s</span>
4 0
4 years ago
I need help and please hurry.
anyanavicka [17]
Hi, time is independent variable. It's stands alone and isn't change by anything.
Temperature is dependant variable (depends on time)
5 0
4 years ago
A 166-g hockey puck is gliding across the ice at 19.5 m/s. A player whacks it with her stick, sending it moving at 43.1 m/s at 4
Andre45 [30]

Answer:

Explanation:

Given

mass of puck=166 gm

initial velocity=19.5 m/s

Final velocity=43.1 m/s at angle of 45^{\circ} to the intial direction

Suppose puck is travelling towards positive x axis

thus initial moment \vec{P_i}=0.166\times 19.5\hat{i}

Final momentum \vec{P_f}=0.166\left ( 43.1cos45\hat{i}+43.1sin45\hat{j}\right )

Impusle=P_f-P_i=5.06\hat{i}+5.06\hat{j}-3.237\hat{i}

I=1.823\hat{i}+5.06\hat{j}

Angle between initial velocity and force

tan\theta =\frac{5.06}{1.823}

\theta =70.18^{\circ} w.r.t x-axis

and Fdt=Impulse

dt=112 ms=112\times 10^{-3} s

\vec{F}=16.339\hat{i}+45.17\hat{j}

|F|=\sqrt{16.34^2+45.17^2}=48.03 N

3 0
3 years ago
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