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hjlf
3 years ago
6

Mg (oh)2chemical name

Chemistry
1 answer:
ikadub [295]3 years ago
5 0
Magnesium Hydroxide is Mg(OH)2
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Different elements emit different emission spectra when they are excited because each type of element has a unique energy level
jonny [76]
Different elements emit different spectra when their electrons get excited because each element has a different arrangement of electrons surrounding the nucleus.  The energy levels in which the electrons can occupy are unique to a specific element. When an electron gets excited into a higher energy level, it will eventually relax back into its original state and emit light corresponding to that energy. 
8 0
3 years ago
How many moles of nitrous oxide (N2O) are produced when 1.40 moles of ammonium nitrate (NH4NO3) decompes?
blagie [28]

Answer:

The answer to your question is 1.40 moles of N₂O

Explanation:

Balanced equation

                           NH₄NO₃   ⇒   N₂O  +  2 H₂O

                                 2   --------   N  ---------- 2

                                 4   -------    H  ---------- 4

                                 3   -------    O  ---------- 3

Process

1.- From the balanced equation, we know that 1 mol of NH₄NO₃ produces 1 mol of N₂O so, we use proportions to find the number of moles produced when 1.40 moles of NH₄NO₃ react.

                           1 mol of NH₄NO₃  ------------- 1 mol of N₂O

                           1.40 moles            --------------   x

                           x = (1.40 x 1) / 1

                            x = 1.40 moles of N₂O are produced

7 0
4 years ago
Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem
belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

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4 years ago
Jeffry was wondering why when he made breakfast, that after he was done cooking, the mass of everything he used was not the same
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Answer:

equivalent exchange forces cancel out but the  substances are affected around the area

Explanation:

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3 years ago
What is molecule?and what is the molecular formulae?​
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A molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts describing the number of atoms of each element present in the molecule. The empirical formula represents the simplest whole-integer ratio of atoms in a compound.
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