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Stells [14]
3 years ago
6

People in the future may well live inside a rotating space structure that is more than 2 km in diameter. Inside the structure, p

eople on the inside of the outer edge will experience 1 g while people halfway to the axis will experience ______________.
a) 0 g
b) 1/2 g
c) 1/4 g
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

option B

Explanation:

given,

diameter of the rotating space = 2 Km

Force exerted at the edge of the space = 1 g

force experienced at the half way = ?

As the object is rotating in the circular part

Force is equal to centripetal acceleration.

at the edge

g = ω² r

ω is the angular velocity of the particle

r is the radius.

now, acceleration at the half way

g' = ω² r'

g' = \omega^2 (\dfrac{r}{2})

g' =\dfrac{1}{2}(\omega^2 r)

g'=\dfrac{g}{2}

People at the halfway experience g/2

hence, the correct answer is option B

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Man A (70kg) and Man B (90kg) are hanging motionless from a platform at rest. What is the tension TA in the top rope if the plat
Damm [24]

Answer:

The tension in the upper rope (top rope), T1 = 1,888 N

Explanation:

The Parameters that were given:

Mass A, M1 = 70kg

Mass B. M2 = 90kg

acceleration, a = 2 m/s2

Assume the rope doesn't have mass, acceleration due to gravity, g

= 9.8 m/s2

The tension, T in a platform = m (a + g)

Then the tension, T1 in the upper rope = m1 (a + g) + T2

Where T2 = Tension in the lower rope

First, we calculate T2

Since the platform accelerates upward the acceleration would be positive

T2 =  m2 (a + g)

T2 = 90kg ( 2 m/s2 + 9.8 m/s2)

T2 = 1,062N

To calculate the tension T1,

T1 = m1 (a + g) + T2

= 70kg (2 m/s2 + 9.8 m/s2) + 1062N

T1 = 1,888 N

3 0
3 years ago
A 3.0 kg ball is lifted two meters upward in two seconds, and a 6.0 kg ball is lifted one meter upward in one second? Which requ
Sav [38]

Answer:

1. They both uses same energy

2. The 6 kg ball requires more power than 3kg ball

Explanation:

Sample 1

m = 3kg

g= 10m/s^2

h = 2m

t = 2secs

W = mgh = 3 x 10 x 2 = 60J

P= w/t = 60/2 = 30watts

Sample 2

m = 6kg

g= 10m/s^2

h = 1m

t = 1sec

W = mgh = 6 x 10 x 1 = 60J

P= w/t = 60/1 = 60watts

They both uses same energy but different power. The 6 kg ball requires more power than 3kg ball

3 0
4 years ago
Suppose y = 2x + 10. Find y if x = -2
san4es73 [151]

Answer:

y = 6

Explanation:

Given parameters:

        Given equation:

                     y = 2x + 10

And supposing; x = -2

Unknown:

y = ?

Solution:

 We are going to solve this problem by substitution;

           y = 2x + 10

  since x = -2; input this into the equation to solve for y;

           y  = 2(-2) + 10 = -4 + 10  = 6

The value of y = 6

4 0
3 years ago
Using a mass of 1. 8 g and the volume displaced by the sample, calculate the sample's density. Question 17 options: 0. 17 g/mL 0
LUCKY_DIMON [66]

The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL

<u>Given the following data:</u>

  • Mass = 1.8 grams
  • Initial volume = 20 mL
  • Final volume = 23 mL

To calculate the sample's density:

First of all, we would determine the volume displaced by the sample;

Volume \;displaced = 23-20

Volume displaced = 3 mL

Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

Density = \frac{Mass}{Volume}

Substituting the given parameters into the formula, we have;

Density = \frac{1.8}{3}

Density = 0.60 g/mL

Read more: brainly.com/question/18320053

8 0
3 years ago
How is work affected when an object is lifted straight up instead of using a ramp? Work will increase.
kifflom [539]
Without friction, the amount of work only depends on the final height,
and is not affected by the route used to get there. 

If the ramp has no friction, then it has no effect on the total amount
of work done.  The work to lift the load straight up is the same.

If the ramp has some friction, then it takes more work to use the ramp
than to lift the load straight up.  Then the work to lift the load straight up
would be less than when the ramp is used.


3 0
3 years ago
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