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Ne4ueva [31]
3 years ago
5

A gas of certain mass occupies a volume of 650cubic centimeterunder a pressure of 750mm Hg.calculate the pressure under which th

e volume of the gas will be reduced by 10 percent of its original volume. Solve it using Boyle's law of equation.

Chemistry
1 answer:
lapo4ka [179]3 years ago
3 0

Answer: 833.3mmHg

Explanation:Please see attachment for explanation

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Jill is making lemonade. She mixes together some water, lemon juice, and sugar. The lemonade is classified as a(n) _________. A)
PolarNik [594]

Hello, Thanks for making your post on brainly!

I would say the best answer is C)Mixture

A mixer is made by combining 2 or more elements, but your not making a new element. And there are no chemical reactions happening to make a new element.

Hope this helps. Have a great day.

8 0
3 years ago
Read 2 more answers
What is the fraction of the hydrogen atom's mass (11h) that is in the nucleus? the mass of proton is 1.007276 u, and the mass of
ololo11 [35]
Hello there!

To determine the fraction of the hydrogen atom's mass that is in the nucleus, we have to keep in mind that a Hydrogen atom has 1 proton and 1 electron. Protons are in the nucleus while electrons are in electron shells surrounding the nucleus. The mass of the nucleus will be equal to the mass of 1 proton and we can express the fraction as follows:

Mass Fraction= \frac{mass 1 Proton}{mass H atom} = \frac{1,007276 u}{1,007825}=0,9995

So, the fraction of the hydrogen atom's mass that is in the nucleus is 0,9995. That means that almost all the mass of this atom is at the nucleus.

Have a nice day!
3 0
3 years ago
What volume (in L) of oxygen will be required to produce 77.4 L of water vapor in the reaction below?
Inga [223]

Answer:

90.3 L

Explanation:

Given data:

Volume of water produced = 77.4 L

Volume of oxygen required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 6 moles of water = 6×22.414 = 134.5 L

Now we will compare:

                               H₂O           :              O₂    

                               134.5         :              156.9

                                 77.4         :             156.9/134.5×77.4 =90.3 L

So for the production of 77.4 L water 90.3 L oxygen is required.

8 0
3 years ago
A sample gas initially occupies 3.35
Strike441 [17]
After i don’t get it
7 0
3 years ago
Refer to the example about diatomic gases A and B in the text to do problems 19 - 27.
soldier1979 [14.2K]

Answer:a

Explanation:

5 0
3 years ago
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