Answer:
Electric field, ![E=5.63\times 10^{16}\ N/C](https://tex.z-dn.net/?f=E%3D5.63%5Ctimes%2010%5E%7B16%7D%5C%20N%2FC)
Explanation:
Given that,
Charge, ![q=1.83\times 10^5\ C](https://tex.z-dn.net/?f=q%3D1.83%5Ctimes%2010%5E5%5C%20C)
We need to find the magnitude of electric field 17.1 cm (0.171 m) above an isolated charge. Electric field at a point is given by :
![E=\dfrac{kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bkq%7D%7Br%5E2%7D)
![E=\dfrac{9\times 10^9\times 1.83\times 10^5\ C}{(0.171\ m)^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%201.83%5Ctimes%2010%5E5%5C%20C%7D%7B%280.171%5C%20m%29%5E2%7D)
![E=5.63\times 10^{16}\ N/C](https://tex.z-dn.net/?f=E%3D5.63%5Ctimes%2010%5E%7B16%7D%5C%20N%2FC)
So, the electric field is
. Hence, this is the required solution.
Answer: D. The elements have the same number of valence electrons
Explanation: The chemical reactivity of elements is governed by the valence electrons present in the element.
The elements present in the same group or vertical column have similar valence configurations and thus behave similarly in chemical reactions or have similar bonding properties.
For Example: Both fluorine and chlorine belong to same family or group and both have 7 electrons in their valence shell and thus accept single electron to attain noble gas configuration.
![F:9:1s^22s^22p^5](https://tex.z-dn.net/?f=F%3A9%3A1s%5E22s%5E22p%5E5)
![F^-:10: 1s^22s^22p^6](https://tex.z-dn.net/?f=F%5E-%3A10%3A%201s%5E22s%5E22p%5E6)
![Cl:17:1s^22s^22p^63s^23p^5](https://tex.z-dn.net/?f=Cl%3A17%3A1s%5E22s%5E22p%5E63s%5E23p%5E5)
![Cl^-:18:1s^22s^22p^63s^23p^6](https://tex.z-dn.net/?f=Cl%5E-%3A18%3A1s%5E22s%5E22p%5E63s%5E23p%5E6)
thus both would bond with a cation bearing a single positive charge.
Answer:
kilogram metre per second square
Answer:
D
Explanation:
Cells are the smallest unit of organizaiton, followed by tissues, organs, organ systems, and then organisms themselves.
Answer:
There always is an acceleration in a curvilinear motion, as the velocity vector changes, so always.