KHP molarity = (3.5/204.22) x (1000/50) = 0.343 M
NaOH volume = 24.65 - 1.85 = 22.8 ml
Molarity of NaOH = (weight/40) x (1000/22.8) = 1.096W
KH₂PO₄ + NaOH → NaKHPO₄ + H₂O
initial 0.343 1.096W 0 0
after reaction (0.343 - 1.096W) 0 1.096W 1.096W
KH₂PO₄ and NaKHPO₄ is considered as buffer and its (H₂PO₄⁻) pKa value is 7.21
phenolphthalein indicator turns pink means it is at the equivalence point
so pH = pKa
by using buffer equation
pH = pKa + log [salt] / [acid]
when pH = pKa so [salt] = [acid]
1.096 W = 0.343 - 1.096W
2.192 W = 0.343
W = 0.156 g
NaOH molarity = 1.096 W = 1.096 x 0.156 = 0.17 M
Molarity of NaOH = 0.17 M
Answer:
22.75 ⁰C.
Explanation:
- The amount of heat added to a substance (Q) can be calculated from the relation:
Q = m.c.ΔT.
where, Q is the amount of heat added,
m is the mass of the substance,
c is the specific heat of the substance,
ΔT is the temperature difference (final T - initial T).
∵ The amount of heat released by Fe = the amount of heat absorbed by water
<em>∴ - (m.c.ΔT) released by Fe = (m.c.ΔT) absorbed by water.</em>
- (4.45 g)(0.45 J/g·⁰C)(final T - 101.0 ⁰C) = (50.0 g)(4.186 J/g·⁰C)(final T - 22.0 ⁰C)
- 2.0025 final T + 202.2525 = 209.3 final T - 4604.
209.3 final T + 2.0025 final T = 202.2525 + 4604
211.3025 final T = 4806.2525.
<em>final T = 4806.2525/211.3025 = 22.75 ⁰C.</em>