Answer:
A = 65.46 u
Explanation:
Given that,
The composition of zinc is as follows :
Zn-64 = 48.63%
Zn-66 = 27.90%
Zn-67 = 4.10%
Zn-68 = 18.75%
Zn-70 = .62%
We need to find the average atomic mass of the given element. It can be solved as follows :
So, the average atomic mass of zinc is 65.46 u.
Missing question: What is the vapor pressure of the solution at 25°<span>C?
n(NaCl) = 100 g </span>÷ 58,4 g/mol.
n(NaCl) = 1,71 mol.
NaCl → Na⁺ + Cl⁻, amount of ions are 2 · 1,71 mol = 3,42 mol.
n(CaCl₂) = 100 g ÷ 111 g/mol = 0,9 mol.
CaCl₂ → Ca²⁺ + 2Cl⁻, amount of ions 3 · 0,9 mol = 2,7 mol.
m(solution) = 1000 ml (1,00 L) · 1,15 g/ml = 1150 g.
m(H₂O) = 1150 g - 100 g - 100 g = 950 g.
n(H₂O) = 950 g ÷ 18 g/mol = 118,75 mol.
<span>water's mole fraction = 118,75 mol </span>÷ (118,75 mol + 2,7 mol + 3,42 mol).
water's mole fraction = 0,95.
p(solution) = 0,95 · 23 mmHg = 21,85 mmHg.
Answer : The correct answer is 109.
Explanation :
Significant figure : It is defined as the each digits of a number have meaning or contribute to the value of the number.
The addition of given digits is,
43.2 + 50.0 + 16.0 = 109.2
As per the question, the given digits has 3 significant figures. But the answer after addition is 109.2 has 4 significant figures.
The addition rule of significant rule is the least precise number of significant figure in any number of the problem determines the number of significant figures in the answer.
Therefore, from the addition rule, the correct answer is 109.
According to the ideal gas law, partial pressure is inversely proportional to volume. It is also directly proportional to moles and temperature. At equilibrium in the following reaction at room temperature, the partial pressures of the gases are found to be PN2 = 0.094 atm, PH2 = 0.039 atm, and PNH3 = 0.003 atm.
<h3>Equilibrium partial pressures</h3>
The initial partial pressures of CO and water are 4.0 bar and 4.0 bar respectively.
The equilibrium partial pressures (in the bar) of CO, H2O, CO2, and H2 are 4−p,4−p, and respectively.
Let p bar be the equilibrium partial pressure of hydrogen.
The expression for the equilibrium constant is
Kp=PCOPH2OPCO2PH2=(4−p)(4−p)p×p=0.1
p=1.264−0.316p
p=0.96 bar.
To learn more about equilibrium constant visit the link
brainly.com/question/10038290
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Answer:
A
Explanation:
vaporization is the process
