Question

in 5 hr, how far can a car go somewhere and return if the average speed going is 48 mi/hr and the average speed returning is 52 mi/hr ?

Answer 1

Answer:

let x be how far the distance can travel

t be the time to"going"

x=t * 48 (going)

x=(5-t) * 52 (returning)

x=124.8

t=2.6hours

a car can go 124.8 miles from staring point and return to the initial points in 5hours

Answer 2

Answer:

124.8 mi

Step-by-step explanation:

Setting up the equation,

$48t_{1} = 52t_{2}\\ t_{1} + t_{2} = 5\\\\ Solving\ the\ system\ of\ equations,\ we\ get,$

$t_{1} = 2.6\\ t_{2} = 2.4\\\\Plugging\ these\ value\ in respective\ equation,we\ get,\\distance = 124.8$