Why is acid always added to water and not the reverse?

Physics

1 answer:

vladimir2022 [97]4 years ago

6 0

Answer:

A lot of warmth is discharged when solid acids are blended in with water. Including increasingly corrosive discharges more warmth. On the off chance that you add water to corrosive, you structure an incredibly thought arrangement of corrosive at first. So much warmth is discharged that the arrangement may bubble viciously, sprinkling concentrated corrosive out of the compartment! In the event that you add corrosive to water, the arrangement that structures is weaken and the limited quantity of warmth discharged isn't sufficient to disintegrate and splash it. So Always Add Acid to water, and never the switch.

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Which statement accurately describes the motion of the object in the graph above over 10 seconds?

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Explanation:

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<h2><u>Hope this Helped!</u></h2>

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A trolley of mass 4 kg moves with a velocity of 0.5 meter per second It colides with a stationary trolley of mass 3 kg. If the t

Luda [366]

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Approximately $0.29\; {\rm m \cdot s^{-1}}$ .

Explanation:

Make use of the fact that total momentum is conserved in collisions.

The momentum of an object of mass $m$ and velocity $v$ is $p = m\, v$ .

The momentum of the two trolleys before the collision would be:

$4\; {\rm kg} \times 0.5\; {\rm m \cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}$ .
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Thus, the total momentum of the two trolleys right before the collision would be $2\; {\rm kg \cdot m \cdot s^{-1}}$ .

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The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass $m = 7\; {\rm kg}$ would continue to be $v = 2\; {\rm kg \cdot m \cdot s^{-1}}$ shortly after the collision.