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rosijanka [135]
3 years ago
9

PLEASE HELP ME ASAP PLEASE PLEASE!!!!!

Physics
2 answers:
Effectus [21]3 years ago
8 0

Answer:bottom left

Explanation:

Black_prince [1.1K]3 years ago
4 0
Answer: bottom left !!!
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An object 5.Ocm in the length is placed at a distance of 20cm in front of convex mirror
andrew-mc [135]

Answer:

Position = \frac{60}{7}\ cm behind the mirror

Nature = Virtual and Erect

Size = \frac{15}{7}\ cm : Diminished

Explanation:

Sign convention-Distance measured to the left of pole is negative and to the right of pole is positive.

Object distance = u = -20 cm

Focal length = f = Radius of curvature/2 = 30/2 = 15 cm

We have to use mirror formula to find image distance.

\frac{1}{u}+\frac{1}{v}=\frac{1}{f}\\ \frac{1}{-20}+\frac{1}{v}=\frac{1}{15}\\ \frac{1}{v}=\frac{7}{60}\\v=\frac{60}{7}\ cm

Since the image distance is positive, it is formed behind the mirror or a virtual image is formed.

Magnification = =\frac{h_{image}}{h_{object}}=-\frac{v}{u}=\frac{60}{7\times20}=\frac{3}{7}

Height of the object = 5 cm

Height of the image = 5\times\frac{3}{7}=\frac{15}{7}\ cm

Since the height of the image is positive and less than the size of object,it is erect and diminished.

4 0
4 years ago
During an early phase of the planet's existence, earth's atmosphere was similar in composition to the atmospheres of mars and ve
KengaRu [80]

The answer is carbon dioxide. This primordial earths’ atmosphere was composed by gasses from degassing of the earth's interior after its formation. It is after the beginning of life that oxygen levels began to rise and levels of carbon dioxide began to reduce in the atmosphere (as a result of photosynthesis).

8 0
4 years ago
A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th
vladimir2022 [97]

As we know that friction force on box is given by

F_s = \mu_s N

here we know that

N = mg

here we have

m = 12 kg

\mu_s = 0.42

so now we have

N = 12(9.8) = 117.6 N

now we will have

F_s = 0.42(12)(9.8)

F_s = 49.4 N

so it required minimum 49 N(approx) force to move the block

5 0
4 years ago
Read 2 more answers
When a space shuttle was launched, the astronauts onboard experienced an acceleration of 32.0 m/s2 . If one of the astronauts ha
jarptica [38.1K]

Answer:

F = 1280 N

Explanation:

Given that,

Acceleration experienced by a space shuttle, a = 32 m/s²

Mass of the astronauts, m = 40 kg

We need to find the force experienced by the astronaut.

We know that the net force is equal to the product of acceleration and its mass. So,

F = ma

F = 40 kg × 32 m/s²

So,

F = 1280 N

So, 1280 N of force is experienced by the Astronaut.

8 0
3 years ago
Which tool would be most useful to identify areas with frequent earthquakes to predict future earthquakes?
enyata [817]
It is a seismograph that would be most useful.
6 0
3 years ago
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