Answer:
See explanation
Explanation:
When we have to write an organic molecule, we have to remember the <u>IUPAC rules.</u> In this case, we have: "2,5-dimethylfuran". We can divide the name into two parts:
<u>a) "2,5-dimethyl"</u>
<u>b) "Furan"</u>
For part a) we have the indications of the <u>"subgroups</u>" bonded to the main structure, in this case, we have 2 <u>methyl groups</u> (
) bonded to carbons 2 and 5.
For part b) we have the main, structure. In this case furan, this compound is a <u>cyclic structure</u> of 5 members in which we have in the middle of the molecule an oxygen atom and 2 double bonds (see figure 1).
Finally, when we add the methyl groups to the furan we will get the 2,5-dimethylfuran. (see figure 2).
I hope it helps!
He rented the horse for 5 hours because $5 x 5 hours = $25
$25 + 12 = $37
Answer:
18.76atm
Explanation:
Using the formula V1P1/T1 = V2P2/T2, from combined gas law. Volume is constant since we have not been given. Therefore the formula comes to be; P1/T1 = P2/T1
To get P2 = T2(P1/T1)
Where P2 is final pressure
P2 = 239K ( 23atm/293K)
=18.76atm
Answer:
1s^2 2s^2 2p^6 3s^1
Explanation:
electron configuration of an element gives description of the distribution of electron in it's orbital of the atom, the superscript symbolize number of electron been hold by them.
The element here is sodium, which is a alkali metal
mass number =23
Number of proton= 11
electron must be seen in thelowest-energy subshell that is available in the the 3s orbital,
Hence, the electronic configuration is
1s^2 2s^2 2p^6 3s^1
The balanced equation of NaOH and H2SO4 would be:
2NaOH + H2SO4 = Na2SO4 + 2H2O
To determine the concentration of NaOH, we first find the moles of NaOH used in the reaction. We start with the the concentration and volume of H2SO4. We do as follows:
2.00 M H2SO4 ( 0.25 L ) = 0.5 mol H2SO4
0.5 mol H2SO4 ( 2 mol NaOH / 1 mol H2SO4) = 1 mol NaOH
Molarity = 1 mol NaOH / 2.00 L NaOH solution = 0.5 M NaOH solution
