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tiny-mole [99]
2 years ago
14

A solid block of metal is at its melting temperature. it takes 24j to melt 6kg of a metal. what is the latent heat of fusion of

the metal?
Physics
1 answer:
Marina86 [1]2 years ago
8 0

The Latent heat of fusion is also known as the Enthalpy of Fusion. It is a kind pf change in enthalpy.

<h3>Brief explanation of Latent Heat of Fusion? </h3>

The latent heat of fusion, is the change in enthalpy that takes place when energy, typically heat, is provided to a specific quantity of a substance to causes it to change from a solid state to a liquid state at a constant pressure.

For instance, 1 kilogram of ice melts at 0 °C at a variety of pressures, absorbing 333.55 kJ of energy without causing a change in temperature.

The heat of solidification, which occurs when a substance changes from a liquid to a solid, is equal and opposing.

This energy includes the contribution necessary to displace its surroundings against ambient pressure in order to accommodate any corresponding change in volume.

The melting point or the freezing point, depending on the situation, is the temperature at which the phase transition takes place. Conventionally, unless otherwise stated, the pressure is taken to be 1 atm (101.325 kPa).

<h3>Calculation</h3>

The formula of latent heat of fusion is L= q/m

Here q is the heat provided and m is the mass of the object.

So, L = 24j/6kg

L= 4j/kg

So, the latent heat of fusion is 4 j/kg

To know more about latent Heat of Fusion visit:

brainly.com/question/28044951

#SPJ4

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On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the
Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

\frac{F_E}{F_G}=\frac{qE}{mg}              (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

F_E-F_G=ma\\\\a=\frac{qE-mg}{m}

you replace the values of all variables:

a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0
3 years ago
A power station burns 75 kilograms of coal per second. Each kg of coal contains 27 million joules of energy.
Kaylis [27]

Answer:

Explanation:

a )

one kg of coal gives energy of 27 x 10⁶ J

75 kg of coal gives energy of 27 x 10⁶ x 75 J

So rate which energy is coming out of coal per second

= 27 x 10⁶ x 75 J

= 2025 x 10⁶ J /s

2025 million watts .

b ) energy output = 800 million watts

efficiency = (800 / 2025) x 100

= 39.5 % .

3 0
3 years ago
What is required to bring about phase change?
Sauron [17]
To change of phase from gaseous to liquid.....The amount of energy required to change a unit mass of a subtance from solid to liquid (and vice versa)
4 0
3 years ago
Read 2 more answers
A 5.22-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.10 m/s and its y component o
Mamont248 [21]

The magnitude of the object's velocity is

         √ (5.1² + 2.82²)  =  √ (33.9624)  =  5.828 m/s .

Kinetic energy = (1/2) (M) (speed²)

                       =  (1/2) (5.22 kg) (5.828 m/s)²

                       =     (2.61 kg) (33.9624 m²/s²)

                       =          88.64    kg-m²/s²

                       =          88.64  Joules
4 0
3 years ago
The daily average insolation on the earth surface is approximately 6 kWh/m2 (ignoring cloudy weather). If a commercially availab
miv72 [106K]

Answer:

The area is 15.502 km².

The fraction is \dfrac{31}{218500}

Explanation:

Given that,

Daily average insolation = 6 kWh/m²

Efficiency = 20%

Population  = 324 million

Per capita power = 1378 watts

Area of tennessee = 109250 km²

We need to calculate the daily power required

Using given data

daily\ power=population\times Per\ capita\ power

Put the value into the formula

daily\ power = 324\times10^{6}\times1378

daily\ power=4.4647\times10^{11}\ watts

daily\ power=4.4647\times10^{8}\ kW

We need to calculate the total energy per day

Using given data

E=6\tiimes24

E=144\ kW/m^2

We need to calculate the out of total energy

Using energy and efficiency

E'=E\times\eta

E'=144\times\dfrac{20}{100}

E'= 28.8\ kW/m^2

We need to calculate the area

Using formula of area

A=\dfrac{daily\ power}{out\ of\ energy}

Put the value into the formula

A=\dfrac{4.4647\times10^{8}}{28.8}

A=15.502\ km^2

We need to calculate the fraction of Tennessee that is required to power

Using given data

fraction =\dfrac{Area}{tennessee}

Put the value into the formula

fraction =\dfrac{15.502}{109250}

fraction=\dfrac{31}{218500}

Hence, The area is 15.502 km².

The fraction is \dfrac{31}{218500}

6 0
4 years ago
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