Answer: C
Explanation: The warm, wet air in a low pressure system has risen up and cooled down.
Please give Brainliest if you can!
By Newton's second law, we have
So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of
Vietually every electronic device in widespread use contains some form of capacitors .used to store electricity capacitor aften help computer avoid losing their memory when the batteries an being recharged other device such as amplifiers for car steroeos contain capacitor that store energy until it is nedded by the amplifier motiondetector use capacitor to help achieve the proper timing of the until circuit.
m = mass of the partner which the cheerleader lifts = 59.6 kg
h = height to which the partner is lifted by the cheerleader = 0.749 m
g = acceleration due to gravity = 9.8 m/s²
work done by the cheerleader in lifting the partner is same as the potential energy gained by the partner.
W = work done by the cheerleader in lifting the partner
PE = potential energy gained
so W = PE
potential energy is given as
PE = mgh
hence
W = mgh
inserting the values in the above formula
W = 59.6 x 9.8 x 0.749
W = 437.5 J
this is the work done in lifting the partner once.
the cheerleader does this 30 times , hence the total work done is given as
W' = 30 W
W' = 30 x 437.5
W' = 13125 J
Answer:
D) 100 kilometres/hour.
Explanation :
<u>Given</u><u> </u><u>-</u>
- Displacement = 200 km
- Time taken = 2 hrs.
<u>To find</u><u> </u><u>-</u>
- Average velocity of the car.
<u>Solu</u><u>tion</u><u> </u><u>-</u>
★ Velocity = displacement/time
→ V = 200/2
→ v = 100 km/h
<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>average</u><u> </u><u>veloci</u><u>ty</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>car</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>km</u><u>/</u><u>h</u><u>.</u>
